Answer:
3.
Step-by-step explanation:
Find the midpoint of BC:
midpoint = (-1+5)/2, (2-2)/2 = (2, 0).
The slope of BC = (2 - -2) / (-1-5) = -2/3.
Find the equation of the right bisector of BC:
The slope = -1 / -2/3 = 3/2.
y-y1 = m(x-x1)
y - 0 = 3/2(x - 2)
y = 3/2x - 3.
Now find the equation of the median through C:
The midpoint of AB = (1 - 1)/2, (4+2)/2
= (0, 3).
The equation of the median:
The slope = (-2-3) / (5-0)
= -1.
The equation is:
y - 3 = -1(x - 0)
y -3 = -x.
Now we find the point of intersection by solving the 2 equations:
y - 3 = -x
y = 3/2x - 3
y = -x + 3
So:
3/2x - 3 = -x + 3
3/2x + x = 6
5/2 x = 6
x = 12/5.
y = -12/5 + 3
= -12/5 + 15/5
= 3/5.
The sum of the coordinates = 12/5 + 3 /5
= 15/5
= 3.
X² - 4x + y² - 8y = 5
Complete the square:
x² - 4x + (4) + y² - 8y + (16) = 5 + (4) + (16)
→ (x - 2)² + (y - 4)² = 25
Center: (2,4)
radius: √25 = 5
Answer:
x=10
Step-by-step explanation:
Lets use a ratio.
3:2 (12 to 8)
We need to scale the x+4 up 3/2 to be equal to 2x+1
(3/2) x+4 = 2x+1
1.5x+6=2x+1
-1.5x -1.5x
6=0.5x+1
-1 -1
0.5x=5
x=10
You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
