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Andreyy89
2 years ago
6

If you can buy 15 bags of potatoes for $20, then how many can you buy with $4?

Mathematics
2 answers:
Mekhanik [1.2K]2 years ago
8 0

Answer:

Step-by-step explanation:

15 bags for $20 can be represented with 15/20
so x bags for $4 can be represented with x/4

now if you proportion it out (ricochet), 4x15 is 60, 60 divided by 20 is 3, so you can buy 3 bags of potatoes with $4.

OR

you could do 15/20 is 0.75

0.75 times 4 is 3, so $4 can buy you 3 bags.

timofeeve [1]2 years ago
6 0

Answer:

Step-by-step explanation:

Remark

This is a proportion problem. It assumes that if you know 3 of the four parts of a 2 ratio proportion, you can solve for the 4th one.

Givens

number of bags = 15

Cost = 20

Different cost = 4

number of bags = ?

Formula

Number of bags / Cost = different number of bags/ New Cost

Solution

15/20 = x / 4              Multiply both sides by 4

15*4/20  = x / 4 * 4

60/20 = x

Answer x = 3

That is 4 dollars gets you 3 bags of potatoes

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For a school play, Rico bought 3 adult tickets and 5 child tickets for $40. Sasha bought 1 adult ticket and 5 child tickets for
Serhud [2]

The cost of one adult ticket is $7.5 and one child ticket is $3.5

Julia will pay $48 for 5 adult tickets and 3 child tickets.

Step-by-step explanation:

Let,

Cost of one adult ticket = x

Cost of one child ticket = y

According to given statement;

3x+5y=40    Eqn 1

x+5y=25      Eqn 2

Subtracting Eqn 2 from Eqn 1

(3x+5y)-(x+5y)=40-25\\3x+5y-x-5y=15\\2x=15

Dividing both sides by 2

\frac{2x}{2}=\frac{15}{2}\\x=7.5

Putting x=2.5 in Eqn 1

3(7.5)+5y=40\\22.5+5y=40\\5y=40-22.5\\5y=17.5

Dividing both sides by 5

\frac{5y}{5}=\frac{17.5}{5}\\y=3.5

The cost of one adult ticket is $7.5 and one child ticket is $3.5

5 adult tickets = 5*7.5 = $37.5

3 child tickets = 3*3.5 = $10.5

Total = 37.5+10.5 =$48

Julia will pay $48 for 5 adult tickets and 3 child tickets.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/3071107
  • brainly.com/question/3126500

#LearnwithBrainly

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3 years ago
Find largest three consecutive even integers with a sum is at most 126
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Step-by-step explanation:

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thus add 8 to a term to obtain the next term

33 + 8 = 41

41 + 8 = 49

49 + 8 = 57

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Answer:

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Step-by-step explanation:

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