Answer:
see attached graph on the graph tool
Step-by-step explanation:
The equation of the parabola is
x²-6x-16y+25=0
vertex at (3,1) and focus at (3,5)
Answer:
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
Since the warranty on a machine specifies that it will be replaced at failure or age 4 and the distribution for X is defined between 0 and 5 then if we define the random variable Y ="the age of the machine at the time of replacement" we know that the values for Y needs to be between 0 and 4 or between 4 and and we can define the following density function:
for other case
Now we can apply the definition of expected value and we have this:
And for the second moment we have:
And the variance would be given by:
The money he will save in a year is 6,300.
<u>Step-by-step explanation</u>:
Savings for 1 month = 525
Savings for 1 year = money saved for 1 month 12 months
⇒ 525 12 = 6,300
Answer:
( -2 , 4 ) --- ( -2 , 1 ) ------ ( -4 , 1 )
Step-by-step explanation:
Answer:
20 m
Step-by-step explanation:
The width is half the length, and the perimeter is the sum of the lengths of all sides. We can write the equation of the perimeter as ...
... 60 m = L + L/2 + L + L/2
... 60 m = 3L . . . . . collect terms
... 20 m = L . . . . . . divide by 3