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Anarel [89]
3 years ago
14

50 cents is _____% of the value of a dollar? Idk pls help me

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0

Answer:

50

Step-by-step explanation:

xenn [34]3 years ago
5 0

Answer:

50 Cents is 50% of a dollar

Step-by-step explanation:

There is 100 cents in a dollar, so every 1 cent is 1%, so 50 cents = 50%.

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A construction crew has repaired 1.37 miles of a highway. The total length of the highway to be repaired is 7.9. How many miles
JulijaS [17]

Answer:

Part A: m+1.37=7.9

Part B: 6.53 miles are left to be repaired.

Step-by-step explanation:

Given,

Length of repaired part = 1.37 miles

Total length to be repaired = 7.9 miles

Miles left to be repaired = m

Part A:

Create an equation to show the relationship between the number of miles repaired and the number of miles left to be repaired, m.

Miles left to be repaired + Length of repaired part = Total length to be repaired

m+1.37=7.9

Part B

How many miles are left to be repaired?

Subtracting 1.37 from both sides

6.53 miles are left to be repaired.

Keywords: length, subtraction

Step-by-step explanation:

6 0
2 years ago
EXPERTS/ACE/GENIUSES/TRUSTED HELPERS HELPP ME
Bad White [126]
Answer is B, the graph increases by about 0.28 per year
8 0
2 years ago
Please factorise 16p²-9q² for me<br>​
kirill115 [55]

Answer:

a ^ 2 - b ^ 2 = ( a + b ) ( a - b ) where a = 4p and b = 3q.

( 4p + 3q ) ( 4p - 3q )

7 0
2 years ago
Kite FGHK is shown. <br> What is the value of m?
Georgia [21]

For this case, the first thing to do is to observe that the figure is symmetrical with respect to the FH axis.

Therefore, the following lengths are the same:

GH = HK

So, by equalizing both sides we have:

5m + 1 = 3m + 7

From here, we clear the value of m.

We have then:

5m - 3m = 7 - 1\\2m = 6

m = \frac{6}{2}\\m = 3

Answer:

The value of m is given by:

m = 3

4 0
3 years ago
Read 2 more answers
Simplify 14 to the 15th power over 14 to the 5th power.
cluponka [151]

14^15/14^5=14^(15-5)=14^10

Hope this kinda helps !!
6 0
3 years ago
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