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Naya [18.7K]
3 years ago
10

I can't find the ANSWER​

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

5/8

Step-by-step explanation:

convert 2 1/2 into 4/2 and multiply it by 1/4

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*PLEASE ANSWER DIFFICULT QUESTION* What is the area of the polygon?
LenaWriter [7]

Answer:

Option 4, 64 cm^2

Step-by-step explanation:

The polygon in the shape of a star can be made to be easier to find the area of by cutting it into triangle. For all the "point edges" of the star, we can cut them in half from the vertex to create two right-angled triangles at each edge.

The formula of the area of a triangle is bh/2: the height is given as 6cm, the base is 4cm /2 (after you cut it in half) and so is 2 cm. Since the edges can be cut into two, there are 8 right angled triangles at the edges in total.

To find the area of them:

A=8(bh/2)=8(2*6/2)=48 cm^2

However, we are still missing the part at the centre we haven't found the area of, the square. The area of a square is given by the square of the side length(4cm). Thus, A=4*4=16cm^2

Adding the areas of all the edges and the square:

48 + 16 = 64cm^2

Hence, the area of the polygon is 64cm^2

5 0
3 years ago
Read 2 more answers
PLEASE HELP NEED THIS TO PASS
yaroslaw [1]

The solutions to f(x) = 64 is x = 7 and x = –7.

Solution:

Given data:

$f(x)=x^{2}+15 – – – – (1)

f(x)=64 – – – – (2)

To find the solutions to f(x) = 64.

Equate equation (1) and (2), we get

x^2+15=64

Subtract 15 from both sides of the equation.

x^2+15-15=64-15

x^2=49

x^2=7^2

Taking square root on both sides of the equation, we get

x = ±7

The solutions to f(x) = 64 is x = 7 and x = –7.

5 0
3 years ago
Solve for a side in right triangles
elena55 [62]

Answer:

4.50 = ?

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opposite / hypotenuse

sin 40 = ? / 7

Multiply each side by 7

7 sin 40 = ?

4.499513268 = ?

To the nearest hundredth

4.50 = ?

5 0
3 years ago
If g(x) = 3x + 1, evaluate g(-2).
zloy xaker [14]
G(x) = 3x + 1, evaluate g(-2).

Simply plug in (- 3) in g(x)

g(-2) = 3(-2) + 1

g(-2) = - 6 +1

g(-2) = - 5

4 0
3 years ago
The speed of a car after accelerating for 8 seconds is inversely proportional to its weight. The car weighs 1600 kg and accelera
STatiana [176]

Answer:

With 800 extra kg load: speed = 66.667 km/h

With 2400 extra kg load: speed = 40 km/h

Step-by-step explanation:

Let's call the weight of the car W = 1600 kg, and its speed after accelerating for 8 seconds with this weight S = 100 km/h

If we load the car with 800 extra kg, the total weight will be:

W2 = W + 800 = 2400 kg

The relation between the weights is:

W2 / W = 2400 / 1600 = 1.5

If the weight increased 1.5 times, the relation between the speeds will be 1/1.5 (as they are inversely proportional), so:

S2 / S = 1 / 1.5

S2 = S / 1.5 = 66.667 km/h

If we load the car with 2400 extra kg, the total weight will be:

W3 = W + 2400 = 4000 kg

The relation between the weights is:

W3 / W = 4000 / 1600 = 2.5

If the weight increased 2.5 times, the relation between the speeds will be 1/2.5, so:

S3 / S = 1 / 2.5

S3 = S / 2.5 = 40 km/h

3 0
3 years ago
Read 2 more answers
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