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Sliva [168]
2 years ago
6

About 3/4 of Canadians eat ice cream at least once a month. 3/10 of these people eat vanilla ice cream. What fraction of Canadia

ns eat vanilla ice cream at least once a month? The current population of Canada is 36 million. How many of them eat vanilla ice cream at least once a month?
Mathematics
2 answers:
dedylja [7]2 years ago
6 0

Answer:

27000000 people

Step-by-step explanation:

3/4 times 36 million

lyudmila [28]2 years ago
5 0

Howdy Hey!

Th answer you are looking for is; 8.1 million / 8,100,000

Steps:

First, you figure out what 3/4 of the population in Canada is.

3/4 x 36M = 27,000,000 / 27M

Then you have to figure out what 3/10 of this 27M is.

3/10 x 27M = 8,100,000 / 8.1M

Therefore, about 8,100,000 Canadians eat Vanilla Ice Cream per month.

Hope I helped, Have a good day & Brainliest is always appreciated.

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Answer:

See explanation

Step-by-step explanation:

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Instead of having lots of zeros, you show how many powers of 10 will make that many zeros.

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When comparing small numbers, write these numbers in scientific notation (only one non-xero digit must be before point) and then

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8 0
3 years ago
Prove that (I ,+) is an abelian group<br> where I = Set of integers
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Step-by-step explanation:

First we recall the relevant definitions and properties:

An even integer is an integer that is a multiple of 2, that is, an integer that can be written as 2k2k where kk is also an integer.

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Addition is already associative and commutative over the set of all integers, and has an identity 00 and an inverse −n−n for each integer nn.

Oh, and multiplication of integers distributes over addition (this is important because we’re dealing with multiples of 2 but also with addition. The distributive property is how multiplication relates to addition).

This means we have to show a few things:

Addition is closed over the even integers. This holds due to the distributive property: if you have even integers 2k2k and 2m2m, then 2k+2m=2(k+m)2k+2m=2(k+m) is also an even integer. The odd integers fail this property: for example, 11 is odd but 1+1=21+1=2, which is not odd.

Addition is associative over the even integers. This holds because addition is already associative over the set of all integers: 2k+(2m+2j)=(2k+2m)+2j2k+(2m+2j)=(2k+2m)+2j. The odd integers do satisfy associativity, since they’re also a subset of the integers.

Addition has an identity element over the even integers. Since we already know that 00 is an identity for the set of all integers and 00 is even, this shows that we have an identity for the even integers: 2k+0=2k2k+0=2k. This doesn’t hold for the set of odd integers, because if nn and kk are odd integers and n+k=nn+k=n then k=0k=0, a contradiction since 00 is not odd.

Addition has inverses over the even integers. We already know that integers have inverses, and if 2k2k is an even integer then −k−k is the inverse of kk, so that 2k+2(−k)=2(k+(−k))=2(0)=02k+2(−k)=2(k+(−k))=2(0)=0. This means the even integer 2(−k)2(−k) is the inverse of 2k2k. The odd numbers do satisfy this property, since they’re also a subset of the integers.

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6 0
2 years ago
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NeX [460]

Answer:

y = -x + 10

Step-by-step explanation:

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Slope-Intercept Form: y = mx + b

Step 1: Find slope <em>m</em>

m = (11 - 9)/(-1 - 1)

m = 2/-2

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Step 2: Find y-intercept <em>b</em>

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Step 3: Rewrite linear equation

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6 0
3 years ago
A rettangle is 10 inches smaller than it is wide. The perimeter of the
meriva

Answer:

A. Width = 25   Length = 15

Step-by-step explanation:

Length = L = Width - 10

Width = W

Perimeter of a rectangle

=> 2 (L + B) = 80

=> 2 (W - 10 + W) = 80

=> 2 (2W - 10) = 80

=> 4W -20 = 80

=> 4W -20 + 20 = 80 + 20

=> 4W = 100

=> 4W/4 = 100/4

=> W = 25

Width = 25

Length = 25 - 10 = 15

So, the answer is A.

6 0
3 years ago
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