I will assume that by 'width' you mean the base of the triangle. Then, the area would be 10.89cm^2
Answer:
'
Step-by-step explanation:
2/6, 3/9, 4/12, 5/15, 6/18, 7/21, 8/24 etc.
We are asked to find ratio of two relative intensities. Let's start by rearranging formula for R:

For air-raid siren we have:

For jet engine noise we have:

To find out <span>many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
</span>tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]
2x/5 - X/2 = 40
LCD = 10
2•(2x/5) - 5•(X/2) = 40
4x/10 - 5x/10 = 40
4x-5x/10 = 40
-X/10 = 40
10•(-X/10) = 40 • 10
-X = 400
-X/-1 = 400/-1
X = -400.
I believe the solution is that X = -400.