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denis-greek [22]
4 years ago
11

Sexual reproduction in eukaryotes increases genetic variation. In prokaryotes, transformation, transduction, and conjugation are

mechanisms that increase genetic variation. A fundamental difference between the generation of genetic variation in the two domains is ________.
Social Studies
2 answers:
SIZIF [17.4K]4 years ago
5 0

Answer:

True

Explanation:

FromTheMoon [43]4 years ago
3 0

Answer:

Eukaryotic genetic variation occurs with VERTICAL gene transfer while prokaryotic genetic variation occurs with HORIZONTAL gene transfer

Explanation:

In Eukaryotes, genes lays on top of each since they reproduce sexually this gives rise to their genetic variation and hence the vertical gene transfer, but prokaryotes lie side by side, reproducing by conjugation, transformation and transduction. This makes their genetic variation to be horizontal.

Example is conjugation in Spirogyra.

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melomori [17]

Kylie is a cognitive psychologist. in this case, kylie is most likely to treat Jamal, who suffers from an anxiety disorder, by getting him to recognize and identify irrational and self-defeating beliefs.

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6 0
1 year ago
Read 2 more answers
Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 72 mm Hgmm Hg. Assume hemoglobin is 50
kiruha [24]

Answer:

<em>0.964 or 96.4 %</em>

Explanation:

Hemoglobin is the red component of the red blood cell, it combines with oxygen to keep the body functional. The fractional saturation of hemoglobin is usually computed graphically but the hill equation gives a more specific value.

Calculations:

The hill equation can be expressed as;

Y_{O_{2} } =\frac{(P_{O_{2} })^{h}}{(P_{_{50} })^{h}+(P_{O_{2} })^{h}}

 Where Y_{O_{2} } is the fractional saturation of oxygen =?;

            P_{O_{2} } is the partial pressure of oxygen = 72 mm Hg;

           P_{_{50} is the partial pressure of oxygen when the hemoglobin is 50%    

                 saturated  = 24 mm Hg and;

            h is the Hill coefficient = 3.

Substituting the values into the expression above we have;

Y_{O_{2} } =\frac{(72 mm Hg_{_{} })^{3}}{(24 mm Hg_{_{} })^{3}+(72 mm Hg_{_{} })^{3}}

Y_{O_{2} } = \frac{373248}{13824 + 373248}

Y_{O_{2} }  = \frac{373248}{387072}

Y_{O_{2} } = 0.964

Therefore the fractional saturation is 0.964 or 96.4 %(multiply by 100)

3 0
4 years ago
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Strike441 [17]

Answer:

1.) who

2.) why

3.) when

4.) where

hope that helps!

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3 years ago
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