Question

Please help!! I will make you brainlest.

Answer 1

Answer:

Question 9: x = $15\sqrt{3}$, Question 10: y = $15\sqrt{3}$, Question 11: x = $14\sqrt{3}$, Question 12: y = 21

Step-by-step explanation:

Question 9-10: Right triangles with 45°, 45°, 90° have a special rule, the legs of the triangle are equal, so x = y. Now you can form the statement $2x^2 = 1350$, and because x = $15\sqrt{3}$, so does y.

Question 11-12: Right triangles with 30°, 60°, 90° also have a special rule, the side corresponding to 30° is half the length of the hypotenuse and the side corresponding to 60° is $\sqrt{3}$ times as great as the 60°. x is 2 times as big as $7\sqrt{3}$, so its length is $14\sqrt{3}$. Y is $\sqrt{3}$ as great as $7\sqrt{3}$, so its length is 21.

Answer 2

Answer:

Step-by-step explanation:

These problems are based on triangle ratios. You cannot use the Pythagorean theorem to solve them.

The first triangle is a 45 45 90 degree triangle (I'm talking about the angles), and so, the ratio is 1:1:$\sqrt{2\\}$, so I have to divide the hypotenuse by $\sqrt{2\\}$ to get the legs. The hypotenuse is 15$\sqrt{6}$, so that divided by $\sqrt{2\\}$ is 15$\sqrt{3\\}$. X is the same length as y because of the triangle ratio, so both x and y for the first triangle are 15$\sqrt{3\\}$.

The second triangle is a 30 60 90 degree triangle, so the ratio is x:x$\sqrt{3}$:2x. The short leg is 7$\sqrt{3}$, so 7$\sqrt{3}$ * 2 is the hypotenuse, which is 14$\sqrt{3}$. The long leg is 7$\sqrt{3}$ * $\sqrt{3}$, which is 21. So, x for the second triangle is 14$\sqrt{3}$, and y for the second triangle is 21.