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Arada [10]
3 years ago
14

Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3x + 3.

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Parallel lines have the same slope, but different y-intercepts

The slope of both lines is -2/3

To find the equation that passes through (7, 3) we can use the point-slope formula: y - y1 = m (x - x1)

y - (3) = (-2/3) (x - (7))

y - 3 = -2/3x + 4 and 2/3

y = -2/3x + 7 and 2/3

or

y = -2/3x + 7.67

:)))

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Kaden, Keith, and Kipp compete in a series of daily 3-way races. For each race, the probability that Kaden wins is 1/6, the prob
BlackZzzverrR [31]

9514 1404 393

Answer:

  3/5

Step-by-step explanation:

Let a, b, c represent the probability of a win by Kaden, Keith, and Kipp, respectively.

  P(bc' | a') = P(a'bc')/P(a')

  P(bc' | a') = (1/2)/(1 -1/6) = (3/6)/(5/6) = 3/5

The probability is 3/5 that Keith beats Kipp when Kaden doesn't win.

4 0
3 years ago
A young child throw a ball upwards with an initial velocity of 20 feet/second. The height of the ball (in feets) after t seconds
Levart [38]
If this is a parabolic motion equation, then it is a negative parabola, which looks like a hill (instead of a positive parabola that opens like a cup). Your equation would be h(t)= -16t^2 + 20t +3. That's the equation for an initial velocity of 20 ft/s thrown from an initial height of 3 ft. And the -16t^2 is the antiderivative of the gravitational pull. Anyway, if you're looking for the maximum height and you don't know calculus, then you have to complete the square to get this into vertex form. The vertex will be the highest point on the graph, which is consequently also the max height of the ball. When you do this, you get a vertex of (5/8, 9.25). The 9.25 is the max height of the ball.
7 0
3 years ago
Help! Please:) Amd Thank you!!!
Mrrafil [7]
They get 2/3 because 2 divided by 3=2/3.
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I'm doing elimination in systems of equations how do I solve this?????? Help!!!
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3 years ago
1. what would the effect have been on the calculated formula weight ([9] above) of your unknown as compared to the true formula
kramer

If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.

If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.

To know more about copper, refer to this link:

brainly.com/question/1543891

#SPJ4

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