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PtichkaEL [24]
3 years ago
8

Hey a ny on thiccccccccc

Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:ok then……

Step-by-step explanation:

natka813 [3]3 years ago
6 0

Answer:

WHat ????

Step-by-step explanation:

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Andy and Christopher are measuring a liquid solution using graduated cylinders, Andy uses 3.5 liters of the liquid solution, and
Gre4nikov [31]

Answer:

Ratio = 0.74

Step-by-step explanation:

Represent

- Andy with A

- Christopher with C

A = 3.5L

C = 2580mL

Required

Determine the ratio of C to A

Ratio is represented as thus:

Ratio = C:A

Rewrite as fraction

Ratio = \frac{C}{A}

This gives

Ratio = \frac{2580mL}{3.5L}

Convert L to mL

Ratio = \frac{2580mL}{3.5*1000mL}

Ratio = \frac{2580mL}{3500mL}

Ratio = \frac{2580}{3500}

Ratio = 0.73714285714

Ratio = 0.74 --- Approximated

6 0
3 years ago
0 1 F2
ella [17]
If she has 6 yards and each pillow required 1 yard she can make 6 pillows
7 0
3 years ago
Read 2 more answers
A number is one thousandth of 78,962. What is the number?​
JulsSmile [24]

Answer:

78.962

Step-by-step explanation:

its just moving the decimal

5 0
3 years ago
Help fast. do first question only and please show work thx.
amm1812
Y = -0.01x^2 + 0.5x + 3

when the height y = 8 
-0.01x^2 + 0.5x + 3 = 8
-0.01x^2 + 0.5x - 5 = 0

x =  13.82 and x = 36.18 so the ball is at least 8 ft high   from 13.82 and 36.18 feet inclusive.- from the player.

If the player is 30 ft from the net then the ball is likely to go over the net.
7 0
3 years ago
Given that the employed adult is male, what is the probability that he felt tense or stressed out at work
SVETLANKA909090 [29]
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out  during work were 244 and those that never felt stressed out were 495.
 Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B) 
P(B) is the probability of having a male.
 P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
   and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
                        = 244/739
                         =  0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
3 0
3 years ago
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