A product of two (or more) factor can be zero if and only if at least one of the factors is zero.
In other words, you cannot multiply two non-zero real numbers, and have zero as a result.
So, if we want the product of these two factors to be zero, at least one of them has to be zero.
The first factor is zero if
![x-2 = 0 \iff x=2](https://tex.z-dn.net/?f=%20x-2%20%3D%200%20%5Ciff%20x%3D2%20)
The second factor is zero if
![x+5 = 0 \iff x=-5](https://tex.z-dn.net/?f=%20x%2B5%20%3D%200%20%5Ciff%20x%3D-5%20)
Answer:
0.630
Step-by-step explanation:
Simply evaluating, we get v (0) = 1, v (0.31831) = 0.630, v (2) = 1.566. Thus, the minimum velocity over the interval [ 0, 2] is 0.630.
Using the Theorem of Pythagoras (a² + b² = c²)
Put in the values:
12² + 12² = 28²
Is it correct? (solve)
Nope! Because 12² + 12² = 288, and the square root of 288 is about 17, not 28.
The answer is no, 12cm, 12cm, 28cm cannot form a triangle.
Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
Answer:
Step-by-step explanation:
V = 1/3 * pi * r^2 * h
r = ?
pi = 3.14
h = 17 cm
3*V = pi * r^2 h = r^2 Divide by pi
3*V/pi = r^2 h = r^2 Divide by h
3*V/(pi*h) =r^2 Take the square root of the left to get just r
sqrt(3*V/(pi*h)) = r Now solve the equation.
sqrt(3*538.25 /(3.14*17)) = r
sqrt(1614 / 53.38) =
r = sqrt(30.24)
r = 5.493
<span>W′(6, −6), K′(8, −6), L′(9, −5) , and X′(5, −5) </span>