Step-by-step explanation:
4x+9y=28
-4x-y=-28
8y=0
divide both side by 8
y=0
solve for X in equation 1
4(X)-9(0)=28
4x-0=28
4x =28
divide both side by 4
4x/4=28/4
X= 7
y=0,x=7
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
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Answer:
- 8
Step-by-step explanation:
Given
3x - 6y = 24 ( divide all terms by - 3 )
x + 2y = - 8
