Answer:
The speed is 20.8 m/s
Step-by-step explanation:
If a projectile ascends vertically, and after 3 seconds it reaches its maximum height, calculate the velocity that it carries to the middle of its downward trajectory
Let the maximum height is h and initial velocity is u.
From first equation of motion
v = u + at
0 = u - g x 3
u = 3 g.....(1)
Use third equation of motion
Let the speed at half the height is v'.
An obtuse triangle would be formed. If you add all the angles, you get a total of more then 180 causing it to b obtuse.
To find the solution to this problem, you would do the opposite of division which is multiplication.
Use the terms you have to plug into your new equation;
0.6 x 1.4 = .84
To check your work you would plug in .84 where the '?' is;
.84/.6= 1.4
There you have the original equation you began with.
Therefore, .84 would be your final answer.
Answer:
It should be (2,9).
Step-by-step explanation:
If you rotate it counter clockwise, the x value and y value switch numbers and they will both become postive.
Hey!
Hope this Helps...
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Below, I added what the graph of (x^2)-2 looks like...
The answer is A. (0, -2); Minimum
