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slamgirl [31]
3 years ago
9

Which equations are true?

Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0

B is true because 0-(-x) = 0 + x = x

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H(x) = x3 + 7<br> Determine whether the function is one-to-one.
zubka84 [21]

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

  • passes the vertical line test to make sure it is indeed a function, and
  • also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

h\left(x\right)\:=\:x^3\:+\:7

Have a look at the attached graph.

  • The red portion represents the graph of the function h\left(x\right)\:=\:x^3\:+\:7.
  • The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that h\left(x\right)\:=\:x^3\:+\:7 is indeed a function.
  • The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that h\left(x\right)\:=\:x^3\:+\:7 is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.

6 0
3 years ago
X/5 = 2 1/2<br><br> Fraction <br> Have to find x
nadya68 [22]

Answer:

x=12.5

Step-by-step explanation:

x=2 1/2 times 5

x=12.5

3 0
3 years ago
What is 5(4x+3)= simplified​
cluponka [151]

5(4x+3)=0

20x+15=0

20x = -15

x =  \frac{ - 15}{20}

x =  \frac{ - 3}{4}

4 0
3 years ago
Read 2 more answers
On a coordinate grid what is the distance from g 2,8 to h 2,5
Anika [276]
(2, 8), (2, 5)

Just subtract the numbers that aren't the same.

8 - 5 = 3

So the distance is 3.
5 0
3 years ago
Read 2 more answers
1-sin^2x/sinx-cscx <br><br>How do I solve this problem? I keep getting the wrong answer.
Annette [7]

Answer:

-sinx

Step-by-step explanation:

a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1

with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x

so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx

it is also important to know that cscx is the same thing as 1/sinx

knowing this information, cscx can be replaced with 1/sinx

(cos^2x)/(sinx - 1/sinx)

now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....

cos^2x

---------------------

(sin^2x - 1)/sinx

notice how in the denominator it has sin^2x-1 which is equal to -cos^2x

so now it becomes:

cos^2x

--------------

-cos^2x/sinx

because we have a fraction over a fraction, we need to flip it

cos^2x          sinx

---------- * ----------------

1                  -  cos^2x

because the cos^2x can cancel out, it becomes 1

now the answer is -sinx

3 0
3 years ago
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