Answer and Step-by-step explanation:
we have the following data:
Point estimate = sample mean = \ bar x = 12.39
Population standard deviation = \ sigma = 3.7
Sample size = n = 177
a) the margin of error with a 90% confidence interval
α = 1 - 90%
alpha = 1 - 0.90 = 0.10
alpha / 2 = 0.05
Z \ alpha / 2 = Z0.05 = 1,645
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 1.645 * (3.7 / \ sqrt177)
Outcome:
E = 0.46
b) margin of error with a 99% confidence interval
α = 1-99%
alpha = 1 - 0.99 = 0.01
alpha / 2 = 0.005
Z \ alpha / 2 = Z0.005 = 2,576
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 2,576 * (3.7 / \ sqrt177)
Outcome:
E = 0.72
c) A larger confidence interval value will increase the margin of error.
Hey there! :)
JK ≈ RS
Scale Factor = 9/7
JK = 56
<u>56</u> · <u>9</u> = <u>504</u> = 72
1 7 = 7
Your answer ⇒ B.72
Hope this helps :)
2 is the answer to this equation
Answer:
Part 1) The volume of the ball is 256 cm³
Part 2) The radius of the ball is 3.94 cm
Step-by-step explanation:
Part 1) we know that
The density is equal to divide the mass by the volume
D=m/V
Solve for the volume
The volume is equal to divide the mass by the density
V=m/D
In this problem we have
m=128 g
D=0.5 g/cm³
substitute
V=128/0.5=256 cm³
Part 2) what is the radius of the ball?
we know that
The volume of the sphere (ball) is equal to
we have
assume
substitute and solve for r
Answer:
8^5^7
Step-by-step explanation:
Multiply the numbers:
<u>4</u>X^2 y^3 x <u>2</u>x^3 y^4
<u>8</u>^2 ^3 ^3 ^4
Combine Exponents:
8<u>^2</u> ^3 <u>^3</u> ^4
8<u>^5</u> ^3 ^4
8^5 <u>^3</u> <u>^4</u>
8^5 <u>^7</u>
