Answer: x = 1, y = - 5
Step-by-step explanation:
The given system of linear equations is expressed as
x - 2y = 11- - - - - - - - - - - - -1
- x + 6y = - 31- - - - - - - - - - - -2
We would eliminate x by adding equation 1 to equation 2. It becomes
- 2y + 6y = 11 - 31
4y = - 20
Dividing the the left hand side and the right hand side of the equation by 4, it becomes
4y/4 = - 20/4
y = - 5
Substituting y = - 5 into equation 1, it becomes
x - 2 × - 5 = 11
x + 10 = 11
Subtracting 10 from the left hand side and the right hand side of the equation, it becomes
x + 10 - 10 = 11 - 10
x = 1
Answer:

It's change of subject. :)
Step-by-step explanation:
To me yes.
Algebra is mostly memorization. If you know the formulas and know how to apply it, you should do good.
I say use this. Algebra topics are like building on top each other.
Heart of Algebra:
- Review what the purpose of x in algebra.
- Then learn things like combining like terms, and solving for x.
- Since you know the basics of x, you can then review linear equations( imo, a big content of algebra). Stuff like slope, different linear forms, graphs of linear equations, and mostly linear equation word problems
- Then you can review system of equations. since you know how to manipulate linear equations, etc.
Then move on to other algebra topics dealing with algebra like
- functions, and different types of them
- exponents, and radicals rules
- inequalities.
- sequences.
- These aren't the heart of algebra but study them they are useful and it important to know them.
Since you learned different function rules, we can move on to learning exponetial functions, graphs, and word problems.
Then finally, learn most hard thing in Algebra: Quadratics.
Pratice,practice, and practice and you will pass.
Try to memorize the formulas and know when to apply it.
Good Luck
Answer:

Step-by-step explanation:
The missing parameters are:
--- Cost of marble countertops
--- Cost of retail markup
Required
The cost of marked up price
This implies that we calculate m(c(a))
We have:

can be written as:

Substitute:


Hence, the cost of marked up price is: 
Answer:
X= -4
Step-by-step explanation:
6x + 18 = -6
6x= -24
x= -4