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DedPeter [7]
3 years ago
11

Solve the equation. Enter your answer in the box. x=27−−√3 x=??? HELP ASAP

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0

Answer:

x=-39

Step-by-step explanation:

Ronch [10]3 years ago
5 0

Answer:

3

Step-by-step explanation:

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Which inequality represents the statement? The ages (a) of s group of travelers all exceeded 17 years and were no more then 54 y
klasskru [66]

Answer:

The inequality that represents the age of the group, "x", is: 17 < x \leq 54

Step-by-step explanation:

To express this problem in an inequality we will attribute the age of the members on the group with the variable "x". There are two available information about "x", the first states that every member of the group is older than 17 years, therefore we can create a inequality based on that:

x > 17

While the second data from the problem states that none of than is older than 54 years old, this implies that they can be at most that old, therefore the inequality that represents this is:

x\leq 54

In order for both to be valid at the same time x must be greater than 17 and less or equal to 54, therefore we finally have:

17 < x \leq 54

7 0
3 years ago
The temperature at 9 a.m. is 2 degrees. The temperature rises 3 more degrees by noon. Which expression describes the temperature
Advocard [28]

Answer:

2 + 3

Step-by-step explanation:

6 0
2 years ago
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Need help with school work
vichka [17]
15^2 + 36^2 = 39^2

Your answer is 39
3 0
3 years ago
Read 2 more answers
HELP PLEASE ASAP
Tpy6a [65]

Answer: √20

Step-by-step explanation:

4.47213595 (the 5 repeats)

4 0
2 years ago
A man wants to test for diabetes. His family history shows that the probability of getting diabetes is 0.6. He decides to do a h
lesantik [10]
So,

The probability of the man having diabetes is 0.6 or 60%.  Because we are figuring the probability BEFORE the test is taken that he has the disease, we can disregard the test and its accuracy rate.  That rate is 60%, the probability of him having diabetes.

The correct option is D.
8 0
2 years ago
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