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Olenka [21]
3 years ago
9

Lisa had a starting balance in her checking account of $956.02. She

Mathematics
1 answer:
erik [133]3 years ago
3 0
Letter/ Option A should be correct
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Suppose the equation ax^2+bx+c=0 has no real solution and a graph of the related function has a vertex that lies in the second q
Veseljchak [2.6K]
If it has no real solutions, that means the graph does not intersect the x axis

since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up

so 'a' must be positive



if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
7 0
3 years ago
The degree of the polynomial function f(x) is 4.The roots of the equation f(x)=0 are −6, −2, 1, and 3.Which graph could be the g
nalin [4]
It’s a s 7.47 because of the five and six
5 0
2 years ago
Find the angle between u= V51 - 8; and v= 151+x. Round to the nearest tenth of a degree.
Igoryamba
Not sure if your trying to solve for x or v

6 0
3 years ago
PLEASE ANSWER
melamori03 [73]

Answer:

A. (2,2), (3,2), (3,3), (3,4), (4,6), (5,4), (5,7), (6,4), (6,6), (7,7)

6 0
4 years ago
Read 2 more answers
Help me what’s the answer .
Mandarinka [93]

Answer:

x=3

Step-by-step explanation:

i helped my friend on this before but it was a word problem

8 0
3 years ago
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