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Ymorist [56]
3 years ago
13

Which step would help a student find the molecular formula of a compound from the empirical formula

Chemistry
1 answer:
JulsSmile [24]3 years ago
5 0
Find the mass of the empirical formula.
You must be given a sample of some kind to calculate the weight or know how many moles are present. Then you figure out what one mol would be. The key step is multiplying the empirical formula numbers by what it takes to make 1 mol.

It would be clearer if we were working from some choices.
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How many neutrons does 3919K have?
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19 protons and 19 electrons but neutrons are vary
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Predict what might happen if the human body did not have specialized cells, tissues, organs, and organ systems to maintain homeo
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5. Which of the following can be classified as a mixture ?
podryga [215]

5. B air is a mixture of many elements, but is not a chemically fused.


6. B Beef stew, composition varies throughout.


7. A. They can be chemically separated into their component elements, but they are all homogenous, and as such, have constant composition, which differs from the components properties, as the components must undergo a chemical change to become compounds.

5 0
3 years ago
Which of the following statements best compares the pH value of H3PO4 and HCl?
wel

Answer:

Option B. Both have a pH less than 7, but H3PO4 has a lower pH than HCl

Explanation:

Those are acid, so the pH would be < 7.

H₃PO₄ is a weak acid with 3 dissociations

HCl is a strong acid.

pH depends on [H]⁺

H₃PO₄  →  3H⁺  +  PO₄⁻³

HCl →  H⁺  +  Cl⁻

If both acid, have the same concentration, [H⁺]H₃PO₄ > [H⁺]HCl, that's why the pH from the phosphoric will be lower.

5 0
3 years ago
Identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent for the following equation
bazaltina [42]

The element that gains electrons, becomes reduced.

While the one which loses electrons, becomes oxidized.

In this equation,

CH₃OH + Cr₂O₇²⁻---- --> CH₂O + Cr³⁺.

By balancing the equation, we will get:

3CH₃OH + Cr₂O₇²⁻ + 8H⁺ --> 3CH₂O + 2Cr³⁺ + 7H₂O

Here the oxidation state of Cr changes from +6 to +3 that is it is being reduced thus serving as a oxidizing agent while other element retain their charges.

Here Cr₂O₇²⁻ is reduced while CH₃OH is oxidized.

So Cr₂O₇²⁻ serves as a oxidizing agent, while CH₃OH serves as reducing agent .

4 0
3 years ago
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