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2 years ago

For science i had to create a super hero from an element. i got beryllium.

1 answer:

5 0

Hello :)

You can spell it multiple ways depending on what you like best :)
Here are a few:

Resykae
Reisekae
Resiykay

Hope this helps!
btw, nice name choice :))

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At what temperature will aluminum have a resistivity that is three times the resistivity of tungsten at room temperature? (Assum

umka2103 [35]

Explanation:

At room temperature, resistivity of tungsten is $5.6 \times 10^{-8}$ and the resistivity of aluminium is $2.8 \times 10^{-8}$ .

Temperature coefficient of aluminium ( $\alpha$ ) = $3.9 \times 10^{-3}$

$R_{a} = 3R_{c} = 5.1 \times 10^{-8} \ohm m$

and, $R_{a} = R_{o}(1 + \alpha \times \Delta T)$

= $2.82 \times 10^{-8} (1 + 3.9 \times 10^{-8} \times \Delta T)$

$\Delta T = 207.3^{o}C$

T = $(207.3 + 20)^{o}C$

= $227.3^{o}C$

So, at $227.3^{o}C$ aluminium has resistivity which is three times the resistivity of tungsten at room temperature.

3 0

3 years ago

Compound has a molar mass of 104.01 g.m mole-1

zaharov [31]

Answer:

incomplete question

Explanation:

the question is not complete

3 0

2 years ago

Many systems and technologies have been designed to communicate over long distances. They all send information that has been enc

blagie [28]

The person above above above me is very very good awnswer hope this helps

4 0

2 years ago

Read 2 more answers

8. An atom has 9 protons, which element is it?

ValentinkaMS [17]

Answer:

fluorine

Explanation:

The element fluorine has 9 protons and 9 electrons.

3 0

3 years ago

Read 2 more answers

When 18.5 g of HgO(s) is decomposed to form Hg(l) and O2(g), 7.75 kJ of heat is absorbed at standard-state conditions. What is t

taurus [48]

Answer:

The standard enthalpy of formation of HgO is -90.7 kJ/mol.

Explanation:

The reaction between Hg and oxygen is as follows.

$\text{Hg(l)}+\frac{1}{2}{O_{2}\rightarrow \text{HgO(s)}$

From the given,

Molar mass of HgO = 216.59 g/mol

Mass of HgO decomposed = 18.5 g

Amount of heat absorbed = 7.75 kJ

From the reaction,

The standard enthalpy of formation = $+7.75\times\frac{kJ}{18.5 g}\frac{216.59}{1mol} \,\,= +90.7 kJ/mol$

During the decomposition of 1 mol of HgO , 90.7 kJ of energy absorbed.

For the formation of 1 mol of HgO , 90.7 kJ of energy is release

Therefore, the enthalpy of formation of mercury(II)Oxide is -90.7 kJ/mol

5 0

3 years ago