What is the product3(x)^5(2x^2+4x+1)

kolbaska11 [484]

I prefer D.

It's clear that Kevin took (1/4)x.
Keith took (1/4)x -> kevin's amount
* 2 -> twice.
-1 -> 1 less.

So Kevin + Keith = (1/4)x + (1/4)x * 2 - 1 = (3/4)x - 1.

3 0

4 years ago

-10y + 9x = -9<br> 10y + 5x = -5

RoseWind [281]

The answer is (-1,0) or x=-1 and y=0 :)

5 0

3 years ago

Which number is greater than 7.23 and less than 7.55? 7.59;7.17;7.6;7.3

Step2247 [10]

7.3 also written as 7.30

5 0

3 years ago

Is the value of x=3 find the value of 4x³-2x²+3x

Usimov [2.4K]

Answer:

99

Step-by-step explanation:

4x³-2x²+3x

4×3³-2×3²+3×3

4(27)-2(9)+9

108-18+9

99

5 0

3 years ago

Read 2 more answers

Complete the tasks and answer the questions. Use the 2SD method to estimate the true proportion of the population of your city t

kupik [55]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Using 2SD Method

The confidence interval is

The interval notation : $(0.108 , 0.212 )$

The interval notation and the sample proportion ± the margin of error

notation: $0.16 \pm 0.052$

The interpretation

There is 95% confidence that the true proportion of those that dislike cilantro lie within the upper(0.212) and the lower(0.108) limit of the calculate confidence interval

Using theory-based method

The 95% confidence interval is

The interval notation : $(0.109 , 0.211 )$

The interval notation and the sample proportion ± the margin of error

notation: $0.16 \pm 0.051$

The interpretation

There is 95% confidence that the true proportion of those that dislike cilantro lie within the upper(0.211) and the lower(0.109) limit of the calculate confidence interval

Using theory-based method

The 88% confidence interval is

The interval notation : $(0.120 , 0.200 )$

The interval notation and the sample proportion ± the margin of

error notation: $0.16 \pm 0.040$

The interpretation is

There is 88% confidence that the true proportion of those that dislike cilantro lie within the upper(0.200 ) and the lower(0.120) limit of the calculate confidence interval.

Step-by-step explanation:

From the question we are told that

The number sample size is n = 200

The number of people that dislike cilantro is k = 32

Generally the sample proportion is mathematically represented as

$\r p = \frac{k}{N}$

=> $\r p = \frac{32}{200}$

=> $\r p = 0.16$

Generally 2SD confidence interval is mathematically represented as

$\r p \pm 2\sqrt{\frac{\r p(1 - \r p)}{n} }$

substituting value

$0.16 \pm 2\sqrt{\frac{0.16(1 - 0.16)}{200} }$

=> $0.16 \pm 0.052$

This can also be represented as

$(0.16 - 0.052 , 0.06 + 0.052)$

=> $(0.108 , 0.212 )$

Generally this confidence interval can be interpreted as

There is 95% confidence that the true proportion of those that dislike cilantro lie within the upper and the lower limit of the calculate confidence interval

Using theory-based method estimate 95% confidence interval

Generally from the question the confidence level is 95% hence the level of significance is calculated as

$\alpha = (100 - 95)\%$

=> $\alpha = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the confidence level using theory base method is

$0.16 \pm 1.96 \sqrt{\frac{0.16 (1- 0.16)}{200} }$

=> $0.16 \pm 0.051$

This can also be represented as

$(0.16 - 0.051 , 0.06 + 0.051)$

=> $(0.109 , 0.211 )$

Generally this confidence interval can be interpreted as

There is 95% confidence that the true proportion of those that dislike cilantro lie within the upper(0.211) and the lower(0.109) limit of the calculate confidence interval

Using theory-based method estimate 88% confidence interval

Generally from the question the confidence level is 95% hence the level of significance is calculated as

$\alpha = (100 - 88)\%$

=> $\alpha = 0.12$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } =Z_{\frac{0.12 }{2} } = 1.55$

Generally the confidence level using theory base method is

$0.16 \pm 1.55 \sqrt{\frac{0.16 (1- 0.16)}{200} }$

=> $0.16 \pm 0.040$

This can also be represented as

$(0.16 - 0.040 , 0.06 + 0.040)$

=> $(0.120 , 0.200 )$

Generally this confidence interval can be interpreted as

There is 88% confidence that the true proportion of those that dislike cilantro lie within the upper(0.200 ) and the lower(0.120) limit of the calculate confidence interval

3 0

4 years ago