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3 years ago

What is the product3(x)^5(2x^2+4x+1)

Mathematics

1 answer:

ryzh [129]3 years ago

4 0

Answer: 6x^7+ 12x^6+ 3x^5

Hope that helped

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Listed in the Item Bank are key terms and expressions, each of which is associated with one of the columns. Some terms may displ

NISA [10]

Answer:

i am unsure aswell please let me know.

Step-by-step explanation:

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2 years ago

Read 2 more answers

Need help on this one too

KiRa [710]

I think it's none because that should be communitive and that's not there so.

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2 years ago

Elijah is selling coupon books for a school fundraiser. the coupon books sell for $11. the school gets $8 and $3 goes to elijah'

Sladkaya [172]

He collected $264.00, $72.00 went to his homeroom, and $192.00 to the school

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3 years ago

The table represents an exponential function. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4

scoray [572]

Answer:

The multiplicative rate of change of the function is $\dfrac{2}{3}$

Step-by-step explanation:

You are given the table

$\begin{array}{cc}x&y\\ \\1&6\\2&4\\ \\3&\dfrac{8}{3}\\ \\4&\dfrac{16}{9}\end{array}$

An exponential function can be written as

$y=a\cdot b^x,$

where b is the multiplicative rate of change of the function.

Find a and b. Substitute first two corresponding values of x and y into the function expression:

$6=a\cdot b^1\\ \\4=a\cdot b^2$

Divide the second equality by the first equality:

$\dfrac{4}{6}=\dfrac{a\cdot b^2}{a\cdot b^1}\Rightarrow b=\dfrac{2}{3}$

Substitute it into the first equality:

$6=a\cdot \dfrac{2}{3}\Rightarrow a=\dfrac{6\cdot 3}{2}=9$

So, the function expression is

$y=9\cdot \left(\dfrac{2}{3}\right)^x$

Check whether remaining two values of x and y suit this expression:

$9\cdot \left(\dfrac{2}{3}\right)^3=9\cdot \dfrac{8}{27}=\dfrac{8}{3}\\ \\9\cdot \left(\dfrac{2}{3}\right)^4=9\cdot \dfrac{16}{81}=\dfrac{16}{9}$

So, the multiplicative rate of change of the function is $\dfrac{2}{3}$

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3 years ago

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What is (8 - 3p)( -2 ) using distributive property

Llana [10]

When you use the Distributive Property you're really just multiplying the number on the outside by all of the numbers on the inside of the parentheses.

(8 - 3p) (-2) Multiply -2 by 8 and -3p
-2(8) + (-2)(-3p) Multiply
-16 + 6p

3 0

3 years ago