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Leya [2.2K]
3 years ago
13

How do you work out 9/10 divided by 6/7??

Mathematics
1 answer:
Helga [31]3 years ago
6 0
\frac{9}{10} \div \frac{6}{7}
You just flip 6/7 so it would be 7/6 and then you times it.
\frac{9}{10} \div \frac{6}{7}
\frac{9}{10} \times \frac{7}{6} = \frac{63}{60} = \frac{21}{20} 

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MArishka [77]

Answer:

I believe the answer would be 11/30 longer but you might want to simplify it

3 0
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A driver drove for 3 hours at a certain speed. If he drove 12 more miles at the same speed, the distance would be 132 miles. At
Zinaida [17]
Distance traveled in 3 hrs was (speed in mph)(3 hrs)

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7 0
3 years ago
Which list of numbers is arranged from greatest to least? A. 0.55, 60%, 4 7 4 7 B. 4 7 4 7 ,60%, 0.55 C. 60%, 0.55, 4 7 4 7 D. 6
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4 0
3 years ago
Show that an implicit solution of 2x sin2(y) dx − (x2 + 12) cos(y) dy = 0 is given by ln(x2 + 12) + csc(y) = C. Differentiating
natima [27]

Answer:

See explanation

Step-by-step explanation:

Given the equation:

2x\sin (2y)dx-(x^2+12)\cos ydy=0

Separate variables x and y:

2x\sin (2y)dx=(x^2+12)\cos y dy\\ \\\dfrac{2x\sin (2y)dx}{x^2+12}=\cos ydy\ [\text{Divided by non-zero expression }x^2+12]\\ \\\dfrac{2x}{x^2+12}dx=\dfrac{\cos y}{\sin (2y)}dy\ [\text{Divided by }\sin (2y)]\\ \\\dfrac{2x}{x^2+12}dx=\dfrac{\cos y}{2\sin y\cos y}dy\ [\text{Use formula }\sin (2y)=2\sin y\cos y]\\ \\\dfrac{2x}{x^2+12}dx=\dfrac{1}{2\sin y}dy\ [\text{Simplify when }\cos y\neq 0]

Now,

\int \dfrac{2x}{x^2+12}dx=\int \dfrac{1}{2\sin y}dy\\ \\\int \dfrac{d(x^2)}{x^2+12}=\dfrac{1}{2}\int \dfrac{\sin y}{\sin^2 y}dy\\ \\\int \dfrac{d(x^2+12)}{x^2+12}=-\dfrac{1}{2}\int \dfrac{d(\cos y)}{1-\cos^2 y}\\ \\\ln (x^2+12)+C=-\dfrac{1}{2}\int \left(\dfrac{1}{2(1-\cos y)}+\dfrac{1}{2(1+\cos y)}\right)d(\cos y)\\ \\\ln (x^2+12)+C=-\dfrac{1}{4}\int \dfrac{d(\cos y)}{1-\cos y}-\dfrac{1}{4}\int \dfrac{d(\cos y)}{1+\cos y}\\ \\\ln (x^2+12)+C=\dfrac{1}{4}\ln (1-\cos y)-\dfrac{1}{4}\ln (1+\cos y)

\ln (x^2+12)+C=\dfrac{1}{4}\ln \dfrac{1-\cos y}{1+\cos y}

Find the constant solutions, if any, that were lost in the solution of the differential equation:

When

\cos y=0,

then

y=\dfrac{\pi }{2}+\pi k,\ k\in Z

5 0
3 years ago
Can someone plz help me find the answer to 2x=4 y-16. and 2x-y=-7
telo118 [61]

Answer:

So, y = 2x + 7;

Then, 2x = 4( 2x + 7 ) - 16;

2x = 8x + 28 - 16;

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- 6x = 12;

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Then, y = 2· (-2) + 7;

y = - 4 + 7;

y = 3.

Step-by-step explanation:


8 0
4 years ago
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