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NeX [460]
2 years ago
8

Seymour is twice as old as Cassandra. If 16 is added to Cassandra’s age and 16 is subtracted from Seymour’s age, their ages beco

me equal. What are their present ages? PLEASE SHOW WORK!!!
Mathematics
1 answer:
den301095 [7]2 years ago
6 0
S=2c AND s-16=c+16
Use substitution so...
2c-16=c+16
C=32
S=2c so s=64

Check: s-16=c+16...64-16=32+16...48=48

So Cassandra is 32 and Seymour’s is 64
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Please help me on this problem
Anna71 [15]

Answer:

The pairs of integer having two real solution forax^{2} -6x+c = 0 are

  1. a = -4, c = 5
  2. a = 1, c = 6
  3. a = 2, c = 3
  4. a = 3, c = 3

Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

7 0
3 years ago
i am a solid figure with two congruent polygons that are bases,connected with lateral face that are rectangles.
BabaBlast [244]
Rectangular prisim is the answer
6 0
3 years ago
Is 8/6 greater than or less than 11/12
Zanzabum
\frac{8}{6}\ \ \ \ and\ \ \ \ \frac{11}{12}\ \ \ \ \ | make\ a\ common\ denominator\ 12\\\\
\frac{16}{12}\ \ \ and\ \ \ \ \frac{11}{12}\\\\
Now\ it\ is\ visible\ that\ \frac{16}{12} \ >\ \frac{11}{12}\ so\ \frac{8}{6} \ >\ \frac{11}{12}\ 

8 0
3 years ago
Read 2 more answers
Hey plz anyone inbox me ​
Scilla [17]

Answer:

Hi

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
46,054,202 round the underlined number the 5 isunderlined 
Scrat [10]
<em>if 5 is to be rounded off, then the rule is, if the next significant digit is equal or greater than 5 it adds up, other wise not..</em>
<em>In this case the next significant digit is 0 which is less than 5 so it will not be added up.</em>

<em>46,054,202 ≈ 46,000,000 Answer</em>
8 0
3 years ago
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