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Vika [28.1K]
3 years ago
10

three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.

find each score
Mathematics
1 answer:
jasenka [17]3 years ago
7 0
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
=93

3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)
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Can someone please write an equation to model this scenario which relates to the first two questions. I need it ASAP!
Vika [28.1K]

Answer:

y = 50x + 200

Step-by-step explanation:

the 200 is the y intercept because it is where his pay starts, so even if Matt doesnt make any sales he will still get 200 that week

the slope (50) is determined because that is what will change

if he makes 2 sales he will make 100 + 200 that week, and if he makes 4 sales he will make 200 + 200 that week and so on

7 0
2 years ago
An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let
Advocard [28]

Answer:

P(t)=3,000,000-3,000,000e^{0.0138t}

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

P'(t)=K(3,000,000-P(t))

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

P'(t)+KP(t)= 3,000,000K

The <em>integrating factor </em>is

e^{Kt}

Multiplying both sides of the equation by the integrating factor

e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K

Hence

(e^{Kt}P(t))'=3,000,000Ke^{Kt}

Integrating both sides

e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C

e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C

P(t)=3,000,000+Ce^{-Kt}

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

so

e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138

And the equation that models the number of people (in millions) who become aware of the product by time t is

P(t)=3,000,000-3,000,000e^{0.0138t}

5 0
3 years ago
What is the area of the following circle of the radius is 4=r
maria [59]

Answer:

50.24 (unit squared! cm2, m2, etc.)

Step-by-step explanation:

Area is: Pi x r^2

3.14 x 4^2 = 3.14 x 16 = 50.24

8 0
3 years ago
Read 2 more answers
What is the smallest value in the stem and leaf plot below?
Alexeev081 [22]
Listing the data from the Stem and Leaves table as raw data we have:

02, 03, 03, 07, 10, 10, 17, 34, 34, 35, 35

Hence the smallest value is 02 = 2

Answer: A
7 0
3 years ago
Two less than 3/2 of a number (x) is more than 5 1/2
garik1379 [7]

Answer:

3/2x-2>5 1/2

Step-by-step explanation:

Two less than a number means we are subtracting 2, so we can write it into the equation as -2.

Since we dont know the value of x, we can just write 3/2 of x by multiplying 3/2 by x. So 3/2x. Also, since we are subtracting two from 3/2x, -2 comes after 3/2x.

Now, since it says that it is more than 5 1/2, we could use the greater than sign (>), to express that. So >5  1/2

Our final expression is 3/2x-2>5 1/2.

Hope this helps!

3 0
3 years ago
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