1) 2 points:
We need to come up with a function that intersects the graph at two points, meaning has two (x,y) in common with the function. If you look at the graph of y=x^2, you see that it would be quite easy to draw a line that intersects the graph twice. In fact, there are an infinite number of functions that would satisfy this.
One easy function is y=2. This is a horizontal line in which y=2 for all values of x. In the graph y=x^2, y=2 intersects twice.
2=x^2
x^2= √2 or -√2
the shared points are (√2,2) and (-√2,2)
b) one point:
Here, we want to find an equation with only one (x,y) in common with y=x². This is a bit trickier.
One easy solution is y=-x²
Looking at a graph of the two functions, you see that y=-x² is a reflection across the x-axis of y= x². The two functions have only one point in common: (0,0).
c) no point in common
Take another look at the graph of y=x². You see that the function never crosses the x-axis. A simple function that will never intersect the graph is y=-2. Since y is negative for all values of x, it is guaranteed to never intersect y=x², a function in which y is positive for all negative or positive values of x.
Answer:
Radius of the sphere = ![\sqrt[3]{91.13} \,feet](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B91.13%7D%20%5C%2Cfeet)
Step-by-step explanation:
Volume of a sphere is :

For, Volume = 
As, 
![121.5\times \pi =\dfrac{4}{3}\times \pi \times r^3 \\\\121.5=\dfrac{4}{3}\times r^3\\\\ 121.5\times \dfrac{3}{4} =r^3\\\\r^3=91.13\\\\r=\sqrt[3]{91.13} \,feet](https://tex.z-dn.net/?f=121.5%5Ctimes%20%5Cpi%20%3D%5Cdfrac%7B4%7D%7B3%7D%5Ctimes%20%5Cpi%20%20%5Ctimes%20r%5E3%20%5C%5C%5C%5C121.5%3D%5Cdfrac%7B4%7D%7B3%7D%5Ctimes%20r%5E3%5C%5C%5C%5C%20121.5%5Ctimes%20%5Cdfrac%7B3%7D%7B4%7D%20%3Dr%5E3%5C%5C%5C%5Cr%5E3%3D91.13%5C%5C%5C%5Cr%3D%5Csqrt%5B3%5D%7B91.13%7D%20%5C%2Cfeet)
The radius of the sphere is : ![\sqrt[3]{91.13} \,feet](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B91.13%7D%20%5C%2Cfeet)
Answer:
40 passes
Step-by-step explanation:
If Asher can make 8 passes in 3 football cames, and you need to find how many passes he can make in 15, you need to multiply 8 x 5. This is because he made 5 times as many passes (3 x 5 = 15)
Step-by-step explanation:
calculate the total area of the bottom sections of the back and the two side walls which should be tiled.Give your answer in squared metres rounded a
accurately to 2 decimals
Hi there
The function is
Y (x)=10000 (1-0.02)^x
Y (x)=10000 (0.98)^x
Where x is the number of time
Hope it helps