A function is differentiable if you can find the derivative at every point in its domain. In the case of f(x) = |x+2|, the function wouldn't be considered differentiable unless you specified a certain sub-interval such as (5,9) that doesn't include x = -2. Without clarifying the interval, the entire function overall is not differentiable even if there's only one point at issue here (because again we look at the entire domain). Though to be fair, you could easily say "the function f(x) = |x+2| is differentiable everywhere but x = -2" and would be correct. So it just depends on your wording really.
The x-intercept is 12 and the y-intercept is -2
Answer:
1. -a + b = depends on which integer is bigger, if b is bigger than a, then it would be positive. If -a is bigger, then it will be negative
2. a-(-b) = positive
3. -a * b = negative
a. 87 + 65 b. -58+42
c. 73+(-55) d. -47+(-30)
Step-by-step explanation:
Remember:
two positives(multiply or divide) = positive
two negatives(multiply or divide) = positive
a positive and a negative(multiply or divide) = negative
two positives(addition) = positive, (subtract) = depends on which integer is bigger
two negatives(addition) = positive, (subtract) = depends on which integer is bigger
The answer is 4/5 your welcome
Answer:
<u>The correct answer is A. 1 +/- i √31/2</u>
Step-by-step explanation:
Let's use the quadratic formula to solve the equation:
x² - x + 8 = 0
Let's recall that the quadratic equation is:
x = (-b +/- √(b² - 4ac))/2a
In the equation, a = 1, b = -1, c = 8.
Replacing with the real values, we have:
x = (-b +/- √(b² - 4ac))/2a
x = (- (-1) +/- √(-1² - 4 (-1) (8)))/2(1)
x = (1 +/- √( 1 - 32)/2
x = (1 +/- √( - 31)/2
x = (1 +/- √( -1 * 31)/2
Let's recall that √ -1 = i
x = 1 +/- i √ 31/2
<u>The correct answer is A. 1 +/- i √31/2</u>
