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PSYCHO15rus [73]
3 years ago
11

What is the LCD of 2/7 and 9/10

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0
Assuming LCD means Lowest Common Denominator
Assuming by "and" you mean adding the two

Well, you go by the multiples of 7;
7, 14, 21, 28, 35, 42, 49, 56, 63,<u> 70</u>
Multiples of 10;
10, 20, 30, 40, 50, 60, <u>70</u>, 80, 90, 100

Straight away you can see the lowest common multiple is 70,

Now to go about adding them,
2/7 * 10 (both sides) , 20/70
9/10 * 7 (both sides) , 63/70

Then you add the two; 20/70 + 63/70  - now we can add them because they share the same denominator
20/70 + 63/70 = 83/70 = 1 whole 13/70 (simplified)

<u>The LCD is 70

Quick tip, </u>to find a common multiple (not necessarily the lowest) multiply the two denominators. 
Zigmanuir [339]3 years ago
7 0
The least common denominator or LCD is 70 because for
10=10,20,30,40,50,60,70,80
7=7,14,21,28,35,42,49,56,63,70,77
and 70 is the least common denominator of 10 and 7 so 70 ims your answer
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The answer is 5
Because-9+4= -5
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3 years ago
In a recent year, 33.6% of all registered doctors were female. If there were 44,500 female registered doctors that year, what wa
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Answer:

132,440

Step-by-step explanation:

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6 0
3 years ago
If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experimen
bezimeni [28]

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

The probability of getting a sum of 13 or more.

Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

P(\text{sum=11})=\dfrac{3}{36}

P(\text{sum=11})=\dfrac{1}{12}

Therefore, the probability of getting a sum of 11 in these outcomes is \dfrac{1}{12}.

Sum less than or equal to 4 = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)} = 6

The probability of getting a sum less than or equal to 4 is

P({sum\leq 4})=\dfrac{6}{36}

P({sum\leq 4})=\dfrac{1}{6}

Therefore, the probability of getting a sum less than or equal to 4 is \dfrac{1}{6}.

Sum of 13 or more = empty set because maximum sum is 12.

The probability of getting a sum of 13 or more is

P(sum\geq 13)=\dfrac{0}{36}

P({sum\geq 13})=0

Therefore, the probability of getting a sum of 13 or more is 0.

8 0
3 years ago
If a pound of apples cost $2.90 how much would 2.4 lbs cost
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Answer:

0.0003625

:) Hope that helps :)

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3 years ago
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