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Talja [164]
3 years ago
5

Another 20 Points...

Mathematics
2 answers:
Kobotan [32]3 years ago
8 0

Answer:

Step-by-step explanation:

alright lets get started.

We have given the equation of the circle as

x^2+y^2+16x-24y+159=0

adding and subtracting 64 from above equation

x^2+y^2+16x-24y+159+64-64=0

x^2+16x+64+y^2-24y+95=0

(x+8)^2+y^2-24y+95=0

adding and subtracting 144 from above equation

(x+8)^2+y^2-24y+95+144-144=0

(x+8)^2+(y-12)^2-49=0

(x+8)^2+(y-12)^2=49

Hence, this is the standard form of circle equation,

So, the center of the circle will be (-8,12).    answer

Hope it will help.

kari74 [83]3 years ago
3 0
X^2 + 16x + 64 + y^2 - 24y + 144 = -159 + 64 + 144
(x +8)^2 + (y - 12)^2 = 49
Center: (-8,12)
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