Question

Is △RWS ~ △QWT? yes no

Answer 1

Yes, it is. they are.

Answer 2

Answer: Yes ΔRWS≈ΔQWT.

Step-by-step explanation:

We know that when two chords intersect each other inside a circle, the products of their segments are equal.

Therefore, $QW\times WS=TW\times RW\\\Rightarrow\frac{QW}{RW}=\frac{TW}{WS}$

Now in triangle QWT and triangle RWS

∠QWT=∠RWS     [Vertically opposite angles]

$\frac{QW}{RW}=\frac{TW}{WS}$

Therefore, By SAS similarity rule

ΔRWS≈ΔQWT

Therefore, yes ΔRWS≈ΔQWT.