Answer:
computers are solve all things in are life
Answer:
Given,
P = (22, 1, 42, 10)
Q = (20, 0, 36, 8)
a. Formula for Euclidean Distance :
distance = ((p1-q1)^2 + (p2-q2)^2 + ... + (pn-qn)^2)^(1/2)
Now,
distance = ( (22-20)^2 + (1-0)^2 + (42 - 36)^2 + (10-8)^2) ) ^(1/2)
=( (2)^2 + (1)^2 + (6)^2 + (2)^2 ) ) ^(1/2)
=(4+1+36+4)^(1/2)
=45^(1/2)
Distance = 6.7082
b.Manhattan distance :
d = |x1 - x2| + |y1 - y2|
d = |22- 20| + |1 - 0|
d = |2| + |1|
Explanation:
Answer:
The answer is "Option A".
Explanation:
In the given question the method toString() is used that converts any value into a string. In this code two print method is used, that can be described as follows:
- In the first method, object1 is created, which is used to print all object values.
- In the second method, object1 uses the toString() method, which converts all values into a string, that's why the answer to this question is "True".
Answer:
The answer is letter B.
Explanation:
The option that will most effectively
reduce her or his radiation exposure to that source is Standing 8 ft from the source for 2 minutes.
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
