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Ivanshal [37]
3 years ago
13

Factor completely. x^2−5x−36 Enter your answer in the box.

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

We can factor this using the AC method.

We can split the middle term using the factors 4 and -9

x^2 + 4x - 9x - 36

Factor by grouping.

x(x + 4) - 9(x + 4)

<h3><u>(x - 9)(x + 4) are the factors of this polynomial.</u></h3>
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If cos -105º = -0.26 and csc -105º = -1.03, then cos 105º = ?<br> and csc 105º = ?
labwork [276]
Cos 105 will also be -0.26

csc 105  = 1.03
4 0
4 years ago
Find the equation of the line passing through the point (4,−1) that is parallel to the line 2x−3y=9.
motikmotik

Hey there!

Line passes through (4, -1) & is parallel to 2x -3y=9

Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope.

The given equation needs to be converted into slope-intercept form and we can do this by getting y onto its own side of the equal sign.

Start off by subtracting 2x from both sides.

-3y = -2x + 9

Then, divide both sides by -3.

y = (-2x + 9)/-3

Simplify.

y = 2/3x - 3

"M" is simply a place mat so if we look at our given line, the "m" value is 2/3. Therefore, our slope is 2/3.

We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our new line has a slope of 2/3.

Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (4, -1). Our new slope is 2/3 & it passes through (4, -1).

y-y₁=m(x-x₁)

Let's start by plugging in 2/3 for m (our new slope), 4 for x1 and -1 for y1.

y - (-1) = 2/3(x - 4)

Simplify.

y + 1 = 2/3 + 8/3

Simplify by subtracting 1 from both sides.

y = 2/3x + 8/3 - 1

Simplify.

y = 2/3x + 5/3

~Hope I helped!~

7 0
4 years ago
Someone please help!!!
mel-nik [20]

Answer:

The correct answer is B

Step-by-step explanation:

.. .........

8 0
3 years ago
Read 2 more answers
John bought 6 dumplings for $3.00.
zubka84 [21]
Just make the slope as 1/2 remember rise over run and start at 0
3 0
4 years ago
Find the volume of the solid whose base is the circle x2+y2=25 and the cross sections perpendicular to the x-axis are triangles
ivanzaharov [21]

Triangles with height h and base b, with b=h have area \dfrac{b^2}2.

Such cross sections with the base of the triangle in the disk x^2+y^2\le25 (a disk with radius 5) have base with length

b(x)=\sqrt{25-x^2}-\left(-\sqrt{25-x^2}\right)=2\sqrt{25-x^2}

i.e. the vertical (in the x,y plane) distance between the top and bottom curves describing the circle x^2+y^2=25.

So when x=4, the cross section at that point has base

2\sqrt{25-16}=6

so that the area of the cross section would be 6^2/2 = 18.

In case it's relevant, the entire solid would have volume given by the integral

\displaystyle\int_{-5}^5\frac{b(x)^2}2\,\mathrm dx=4\int_0^5(25-x^2)\,\mathrm dx=\frac{1000}3

6 0
3 years ago
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