<span>You did not include the equations that you want to assess whether they can be used to solve for the radius (r).
Likely, the equation of the circumference, C = 2*Pi*r is included, if so => r = C / (2*Pi).
If you round Pi to 3.14, the equation may be written r = C / 6.28.</span>
The x² term will be C(5,2)x²·2³ = 80x².
The coefficient is 80.
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C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10
Answer:
Step-by-step explanation:
A is a subset of B while B is the universal set.
AB = A U B
A is a subset of B. That is A is contained in B.
Answer:
3x
Step-by-step explanation:
