Which of the following is not an undefined term?

Mathematics

1 answer:

olganol [36]3 years ago

4 0

Which of what following? Is it suppose to be multiple choice?

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Penelope made note of all the bicycles and cars she could see parked or locked on acertain city block. All the cars had exactly

lesantik [10]

Given:

The number of cycles is, n (s) = 7.

The number of wheels in the cycle is, n (sw) = 2.

The number of cars is, n (c) = 15.

The number of wheels in the car is, n (cw) = 4.

The obective is to find the total number of wheels.

The total number of wheels is,

$\begin{gathered} T=n(sw)\cdot n(s)+n(cw)\cdot n(c) \\ =2\cdot7+4\cdot15 \\ =14+60 \\ =74\text{ whe}els \end{gathered}$

Hence, there are 74 wheels in the block.

If there are x bicycles and y cars, the equatioin will be,

$\begin{gathered} T=n(sw)\cdot x+n(ce)\cdot15 \\ T=2x+4x \end{gathered}$

Hence, the number of wheels for x bicycles and y cars is 2x+4x.

6 0

1 year ago

This problem is correct??

ale4655 [162]

yes you are correct evreything is correct

6 0

4 years ago

the sum of the digits of a two number is 14 .if 36 is substracted from the number,the places of the digits are reversed.find the

Taya2010 [7]

The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x

Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y

10y+ x-36=10x+y
Substitute y with 14-x
So we would get

10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5

Y=14-x
=14-5
=9

So the two digit number is
10y+x
=90+5
=95

5 0

3 years ago

B-c,when b=8 and c=7

elixir [45]

If I understand your question correctly then it's simple all you have to do is use the numbers in the place of the b and c so the question would be what is 8-7 which equals 1

8 0

3 years ago

Undo the half of what was left amount. Multiply 2

34kurt

Answer:

the three numbers below are your answers. (in order)

Step-by-step explanation:

$2*2=4\\4+5=9\\9+8=17$

6 0

3 years ago