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3 years ago

What additional information is needed to prove that the triangles are congruent using the AAS congruence theorem?

Mathematics

1 answer:

forsale [732]3 years ago

9 0

It’s b (OA= MA.) I took this quiz last week :)

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Anestetic [448]

3. Answer: a) RT

b) XZ

c) TS

4. Answer: a) 26

b) 58

c) 21.5

d) 127

<u>Step-by-step explanation:</u>

2(PT) = AE 2(CP) = AN 2(CT) = EN

2(13) = AE 2(29) = AN 2(CT) = 43

26 = AE 58 = AN CT = 21.5

Perimeter = AE + AN + EN

= 26 + 58 + 43

= 127

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

20 points! Will mark the brainliest!

andrew-mc [135]

$\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }$

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Write the divide fraction horizontally:
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$= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}$

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Factorise the numerators and denominators when possible:
-----------------------------------------------------------------------------------

$= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}$

-----------------------------------------------------------------------------------
Convert the divide fraction to multiplication fraction
-----------------------------------------------------------------------------------

$= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}$

-----------------------------------------------------------------------------------
Cancel the factors
-----------------------------------------------------------------------------------
$= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}$

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Combine to single fraction
-----------------------------------------------------------------------------------

$= \dfrac{1}{4(x+2)^2}$

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3 years ago

Directions for making a quilt say tkbcut fifteen squares with side that are 3.625 inches long what. Is side length written as a

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3.625 = 29/8 as a fraction. Is that what you're asking?

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Answer:

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2 years ago