3 years ago

1. Solve for x. (3x + 23)

Mathematics

1 answer:

Greeley [361]3 years ago

4 0

Step-by-step explanation:

ummmmmmmmmmmmmmmmm i really wish i coud help but im not sure what is it i thik it mit be =3x+23

but i could be rong pls dont be mad if it is

You might be interested in

The two figures shown below are congruent. Identify the corresponding sides and angles.

padilas [110]

Can you take a pic of the problem?

5 0

3 years ago

Okokokokokokoookokokokokokkokokokookkookokokokoko werewolves or vampires im a werewolve

victus00 [196]

Answer:

auuuuuuuuuuuuuuuu

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the solutions of the equation x4 − 2x3 − x2 + 2x = 0. (Enter your answers as a comma-separated list.)

Bad White [126]

Answer:

$S=\left \{ 0,-1,1,2 \right \}$

Step-by-step explanation:

There are several ways to solve this quartic equation. But since the coefficients, they repeat a=1,b=2,c=1,d=2, but e=0, and they are multiple of each other, then it is more convenient to work with factoring as the method of solving it.

As if it was a quadratic one.

$x^{4}-2x^{3}- x^{2} + 2x = 0\\x(x^{3}-2x^{2}-x+2)=0 \:Factoring \:out\\x[(x^{3}-2x^{2})+(-x+2)]=0 \:Grouping\\x[\mathbf{x^{2}}(x-2)+\mathbf{-1}(x+2)]=0 \:Rewriting\:the\:first\:factor\\x(x^{2}-1)(x-2)\:Expanding \:the \:first \:factor\\x(x-1)(x+1)(x-2)=0\\x=0,x=1,x=-1,x=2\\S=\left \{ 0,-1,1,2 \right \}$