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3 years ago

Please help me with this tenmarks question there's a picture

Mathematics

1 answer:

forsale [732]3 years ago

4 0

The last answer is correct, "Dave is equally likely to select an even number as an odd number."
Numbers 1-10:
1
2
3
4
5
6
7
8
9
10
Out of those, 5 are even and 5 are odd.
So that means there's an equal chance that he selects an odd number as the chance of selecting an even number.

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What is 4% as a simplified fraction?

zysi [14]

4% is the same as .04 and 4/100. 4/100 can be simplified to 1/25 by dividing both sides of the fraction by 4

7 0

4 years ago

Chuck lives of a mile from the post office. He walked of the way from home to the post office. How far did Chuck walk? If possib

Radda [10]

Complete question :

Chuck lives 4/5 of a mile from the post office. He walked 2/3 of the way from home to the post office. How far did Chuck walk? If possible, write the answer in reduced form

Answer:

8/ 15 miles

Step-by-step explanation:

Given that:

Distance from house to post office = 4/5 miles

Distance walked = 2/3 of the distance

Hence, the distance walked can be obtained thus :

2/3 of (4/5)

2/3 * 4/5

8 / 15

Hence, Chucks walked 8 /15 miles

4 0

3 years ago

Jack is mowing a lawn that has a shed. needs to know area of lawn to mow. dimensions of yard are 5x by 13 x-4 . she'd are 2x by

Elena-2011 [213]

The diagram of the lawn and the shed is shown below.

The area of the lawn needed to be mowed equals to the area of the yard minus the area of the shed

The area of the yard = $(5x)(13x-4) = 65 x^{2} -20x$
The area of the shed = $(2x)(2x+4)=4 x^{2} +8x$

The area of the lawn = $65 x^{2} -20x-(4 x^{2} +8x)$
The area of the lawn = $65 x^{2} -20x-4 x^{2} -8x$
The area of the lawn = $61 x^{2} -28x$

5 0

3 years ago

Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 138 to 190 cm and

mart [117]

Answer:

Best predicted value of y' = 86.16 kg

Step-by-step explanation:

Given,

n = 100

Range of heights = 138 - 190cm

Range of weight = 39 to 150 kg

x' =167.46 cm

y' = 81.44 kg

r = 0.108

p value = 0.285

y = - 105 + 1.08x

Significance level = 0.05

We reject H0 since pvalue, 0.285 is less than significance level of 0.05.

Therefore,

Given height of adult male, x = 177 cm

y = - 105 + 1.08x

The best predicted value of y' =

y' = - 105 + 1.08(177)

y' = 86.16 kg

The best predicted value of y' is 86.16kg

6 0

4 years ago

Select the correct answer.

shutvik [7]

B is the answer but check if u can simplify it

3 0

3 years ago