The correct option is "d".
Given that L = 0.8T²
length of pendulum = 30ft
L= 0.8T²
30 = 0.8T²
T² = 30 / 0.8
T² = 37.5
T = √37.5 = 6.1 seconds
<span>So, 6.1 is the closest to the period in seconds for a pendulum that is 30 ft long.</span>
24 students forget their pencil out of 120 students.
Answer: 36 units squared.
Explanation:
Area of a traingle is given by,
| 0.5{x1(y2-y3) + x2(y3-y1) + x3(y1-y2)} |
Accepting the values of the coordinates in x's and y's,
x1 =0, y1=0
x2=3, y2=8
x3 =9, y3=0
= | 0.5 × (-72)|
= 36 unit squared.
Answer:
Step-by-step explanation:
a. 5/2 ÷ 1/2 =
b. 6/9 ÷ 5/6
c. 3/6 ÷ 2/5
d. 7 1/2 ÷ 6
=
e. 1 1/3 ÷ 1 2/3=
- 4/3 ÷ 5/3 =
- 4/3 * 3/5 =
- 4/5
