Question

In ΔMNO, the measure of ∠O=90°, the measure of ∠N=70°, and OM = 3.3 feet. Find the length of MN to the nearest tenth of a foot.

Answer 1

Answer:

3.5 ft

Step-by-step explanation:

MN/sinO = OM/sinN

using the law of sin

MN/sin(90) = 3.3/sin(70)

MN = 3.511786649,

hope this was helpful..

if it was please mark me as brainliest :)

Answer 2

Answer:

3.5 ft

Step-by-step explanation:

MN/sinO = OM/sinN

MN/sin(90) = 3.3/sin(70)

MN = 3.511786649