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Jlenok [28]
3 years ago
7

Which expression represents the phase below? 8 less than the product of 6 and a number, x

Mathematics
1 answer:
faust18 [17]3 years ago
3 0
The statement is "8 less than the product of 6 and a number, x." "Less than" indicates subtraction - you will subtract 8 from a number. That number is "the product of 6 and a number, x." "The product" of these numbers will result with multiplication - you are multiplying 6 and x.

All this gives you the expression: 6x - 8.
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Are you ok? Do you need the call 911, or is this an actual question?

Step-by-step explanation:

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Try it<br> Solve the system of equations.<br> 2x + 3y = 1<br> 5x + 2 = 8<br> What is the solution?
Stella [2.4K]

Answer:

x=6/5 ,y= -7/15

Step-by-step explanation:

we are going to solve this simultaneously.

2x+3y=1.......(i)

and

5x+2=8

5x=6

x= 6/5 .......(ii)

Now let's put value of x into equation number (i)

2x+3y=1

2(6/5) +3y=1

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3y= 1-(12/5)

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3 0
3 years ago
I need help plz!! thx
masya89 [10]

Answer:

2nd statement describes the relation between graph of f(x) and graph of g(x).

Step-by-step explanation:  

We are told that graph of g(x)=f(x)-1 and we are asked to choose the correct statement that describes the relation between graph of f(x) and graph of g(x).

The rules for the translation are as follows:  

f(x-h)=\text{Graph shifted to right by h units}

f(x+h)=\text{ Graph shifted to left by h units}

f(x)+h=\text{ Graph shifted upward by h units}

f(x)-h=\text{ Graph shifted down by h units}    

Upon comparing our given translation with above rules we can see that our parent graph f(x) is shifted down by 1 unit to get our new graph g(x).

Therefore, graph of g(x) is the graph of f(x) translated 1 unit down and 2nd option is the right choice.    

7 0
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Tatiana [17]

Answer:

0 = log_{10} 1

Step-by-step explanation:

Base for the exponent and for the logarithm are the same!

10^0 is the <u>exponential</u> form where 10 is the base and 0 the exponent

log_{10} 1 is the l<u>ogarithm</u> form where 10 is the base

To solve log_{10} 1 =   ask the question :

To what power should I raise the base 10 to obtain the number 1 ?

The answer to the power 0 therefore

log_{10} 1 = 0

1 = 10^{0}   -is-the- exponential -form\\0 = log_{10} 1 - is -the -logarithmic -form

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