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Tanzania [10]
3 years ago
15

EXPAND:

Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

\displaystyle  A) 5\log( {x}^{}   )  +   2 \log( {y}^{} )

Step-by-step explanation:

we would like to expand the following logarithmic expression:

\displaystyle   \log( {x}^{5}  {y}^{2} )

remember the multiplication logarithmic indentity given by:

\displaystyle \rm  \log( \alpha  \times  \beta ) \iff  \log( \alpha ) +  \log( \beta )

so our given expression should be

\displaystyle   \log( {x}^{5}   )  +    \log( {y}^{2} )

by exponent logarithmic property we acquire:

\displaystyle   5\log( {x}^{}   )  +   2 \log( {y}^{} )

hence, our answer is A

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Insert four arithmetic means between -1 and 14
34kurt

Answer:

Step-by-step explanation:

d = 7%2F2

-2, -2+7%2F2, -2+2%287%2F2%29, -2+3%287%2F2%29, 12

-2, -4%2F2+7%2F2, -4%2F2+14%2F2, --4%2F2+21%2F2, 12

-2, 3%2F2, 10%2F2, 17%2F2, 12

 

-2, 3%2F2, 5, 17%2F2, 12

5 0
3 years ago
Rewrite the decimal as the front as a fraction in simplest form 0.27
torisob [31]
So .27 means .27/1 or 2.7/10 or 27/100 or 270/1000 and so on
6 0
3 years ago
Read 2 more answers
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
3 years ago
If you answer i'll give brainllest
GalinKa [24]

Answer:

the first one but make sure to divide

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
There are no answer choices, if someone can solve this, I'd appreciate it. :)
Semenov [28]
Number of trees that are grew more than 3 feet = 10 + 35 = 45

Number of trees that grew more than 3 feet and is more than 50 yards away = 35

P(3 feet and more than 50 yards) = 35/45 = 7/9

Answer: 7/9
5 0
3 years ago
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