i am on this exact question and i am confused myself because it seems like the answer should be "180 degree rotation with a translation of 5 units to the right" but that is not an option :/ so my best guess is either A or D hope this helps at all

Step-by-step explanation:

3 0

3 years ago

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The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3

viva [34]

Answer:

$M_x$ = 8

$M_y$ = 6

Therefore the co-ordinate of the center of mass is = $(\frac{4}{5},\frac{3}{5})$

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

$M_x$ = ∑(mass × x-co-ordinate)

$M_y$ = ∑(mass × y-co-ordinate)

Therefore

$M_x$ = (4×2)+{3×(-3)}+(3×3)

$M_y$ = {4×(-3)}+{3×1}+(3×5)

The x co-ordinate of the center of mass is the ratio of $M_x$ to the total mass.

The y co-ordinate of the center of mass is the ratio of $M_y$ to the total mass.

Total mass (m) = m₁+ m₂+ m₃

= 4+3+3

=10

The x co-ordinate of the center of mass is $\frac {8}{10} = \frac {4}{5}$

The y co-ordinate of the center of mass is $\frac{6}{10}=\frac{3}{5}$

Therefore the co-ordinate of the center of mass is = $(\frac{4}{5},\frac{3}{5})$

4 0

3 years ago