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inn [45]
3 years ago
11

A) 289.6 divide by 6.4 b) 236.592 divide by 0.36

Mathematics
2 answers:
Goryan [66]3 years ago
5 0

Answer:

A,,45.25

B,657.2

Step-by-step explanation:

its the answer

Simora [160]3 years ago
3 0

Answer:

a)45.25

b)657.2

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GIven that GR= x+5 and GP= 2x-3 which expression below calculates the perimeter of this gate? (x+5) + (2x-3) (x+5) + (2x-3) 2(x+
WINSTONCH [101]

Answer:

P = 2(x + 5) + 2(2x - 3)

Step-by-step explanation:

GIven that GR= x+5 and GP= 2x-3 which expression below calculates the perimeter of this gate?

The shape of the gate is rectangular.

Hence, the Perimeter of a rectangle (the gate) = 2L + 2W

Where :

L = GR = x + 5

W = GP = 2x - 3

Hence,the perimeter of the gate is

P = 2(x + 5) + 2(2x - 3)

5 0
3 years ago
HELP I REA;LLY WANNA GO TO BED Which side lengths form a right triangle?
belka [17]
The answer is B.


(the equation to solve this with is: a^2 + b^2 = c^2)
7 0
3 years ago
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Please help .................
alexandr1967 [171]
The formula to solve the area of a circle is 3.14 (pi) times the radius (1/2 of the circumference) so 3.14 x 8 = 25.12 so your answer is 25.1
4 0
3 years ago
then difference between the cubes of two numbers is twice the value of the perfect square of a possitive Intiger
PSYCHO15rus [73]
There are many solutions. But what do you mean with a perfect square of a number. I thought a number IS a perfect square or not.

For example, the difference between 2² and 4² = 12, which is twice the number 6, which is √36

The difference between 2² and 6² = 32, which is twice the number 16, which is a perfect square.

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8 0
3 years ago
What is the midpoint of EC ?
sladkih [1.3K]

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

4 0
3 years ago
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