$\: \: \: 2x + 3y = - 6 \\ -2x + 3y = \: \: \: 6 \\ \frac{ + \: \: \: \: \: \: - \: \: \: \: \: \: = - }{ }{} \\ \: \: \: 4x \: \: \: \: \: \: \: \: \: \: \: \: = - 12 \\ \\ x = \frac{ - 12}{4} \\ \\ x = - 3$

now,

$-2( - 3) + 3y = 6 \\ 6 + 3y = 6 \\ 3y = 6 - 6 \\ 3y = 0 \\ y = \frac{0}{ 3} \\ y = 0$

thus, (-3, 0)

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