3 years ago

Find the 70th term of the following arithmetic sequence. 12,17,22,27,...

2 answers:

8 0

Since it starts at 12 and is increasing by 5 each time, the 70th term will be;
12 + 5(70)
12 + 350
362

362 is the 70th term of the sequence.

Marta_Voda [28]3 years ago

5 0

303 is the 70th term

You might be interested in

Please help me ASAP I will give you the Brainliest!!

timama [110]

Hello!

$\large\boxed{z = 75^{\circ}}$

In an isosceles trapezoid, both angles on each side of the base are congruent.

∠z ≅ 75°

∠y ≅ ∠x

Because of this, we can get the angle measure for z easily:

m∠z = 75°

8 0

3 years ago

Two consecutive odd integers have a product of 99. Find all sets of integers that

german

Answer:

9 and 11

Step-by-step explanation:

4 0

3 years ago

How is a prime number different from a composite number

HACTEHA [7]

Prime numbers have more numbers to it when composite is almost like a whole number hope this helped

6 0

3 years ago

Read 2 more answers

What is the answer to 2 + 37* =

Elden [556K]

39 ..................

7 0

4 years ago

Read 2 more answers

A company’s total cost from manufacturing and selling x units of their product is given by: y = 2x2 – 600x + 49,000. How many un

ale4655 [162]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

$y=2x^2-600x+49000$

We need to find the number of units in order to minimize cost.

We first derivative w.r.t. x,

$y'=4x-600$

For critical points:

$y'=0\\\\4x-600=0\\\\4x=600\\\\x=\dfrac{600}{4}\\\\x=150$

Now, we will check whether it is minimum or not.

We will find second derivative .

$y''=4>0$

So, it will yield minimum cost.

Minimum cost would be

$y(150)=2(150)^2-600\times 150+49000\\\\y(150)=\$4000$

Hence, At 150 units, minimum cost = $4000

Therefore, Option 'c' is correct.

3 0

3 years ago