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dedylja [7]
3 years ago
8

one pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.

Find the ratio of the amount of money Mrs. O pays for the swordfish to the amount of money she pays for the swordfish.
Mathematics
2 answers:
myrzilka [38]3 years ago
7 0
<h2>Answer with explanation:</h2>

It is given that:

one pound of swordfish costs as much as 1.5 pounds of salmon.

Let x be the cost of one pound of salmon.

This means that the cost of one pound of swordfish is: 1.5x

Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.

This means that:

2x+3(1.5x)=39\\\\2x+4.5x=39\\\\6.5x=39\\\\x=\dfrac{39}{6.5}\\\\x=6

This means that cost of 1 pound of salmon= $ 6

Hence, cost of 2 pounds of salmon= $ 12  ( since, 6×2=12 )

and cost of 1 pound of swordfish= $ (1.5×6)= $ 9

Hence,

cost of 3 pound of swordfish= $ (9×3)=$ 27

  • Hence, ratio of amount of money she pays for salmon to the swordfish is:

                    12/27= 4/9

                         i.e.   4:9

  • and the ratio of  amount of money she pays for swordfish to the salmon is:

                         9:4

Lostsunrise [7]3 years ago
4 0
For every 2 pounds of salmon she pays for she will get 3 pounds of sword fish with it. 2 to 3 or 2/3 are different ways to Write a ratio for this problem.
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The large gear attached to the pedals connected to the smaller gear

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Correct responses:

Part A: Approximately 10.47 inches

Part B: 300°The d

Part C: Approximately 125.66 inches

Part D: The distance traveled increases by approximately 62.83 inches

<h3 /><h3>Methods used to calculate the above values</h3>

Given:

The radius of the large central gear, <em>r</em> = 4 inches

Radius of the small gear = 2 inches

Part A:

The distance travelled by the larger gear when the angle of rotation is 150° is given as follows;

\displaystyle Distance \ travelled \ by \ larger \ gear = \mathbf{\frac{150^{\circ}}{360^{\circ}} \times 2 \times \pi \times  4 \, inches} = \frac{10}{3} \cdot \pi \ inches

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Part B:

When the small gear travels the same linear distance as the large gear in part A, we have;

\displaystyle Degree \ of \ rotation = \frac{\frac{10}{3} \cdot \pi }{2 \times \pi \times  2 } \times 360^{\circ}= 300^{\circ}

  • The degree of rotation of the small gear = <u>300°</u>

Part C:

The distance travelled, <em>C</em>, by a single rotation of the large gear is given as follows;

C = 2 × π × 4 inches = 8·π inches

The degree of rotation of the smaller gear following one rotation of the large gear is therefore;

Degree  \ of \ rotation = \displaystyle \frac{8\cdot \pi \ inches}{4 \cdot \pi \ inches } \times 360^{\circ} = \mathbf{ 720^{\circ}}

720° = 2 × 360°

1 complete rotation is equivalent to 360°.

Therefore'

720° is equivalent to two complete rotation.

Therefore, the smaller gear and the wheel rotates twice for each rotation of the large gear

The distance the bicycle travels = 2 × The circumference of the wheel

Therefore;

Distance traveled by the bicycle = 2 × 2 × π × 10 inches = 40·π inches

  • Distance traveled by the bicycle = 40·π inches ≈ <u>125.66 inches</u>

Part D:

If the radius of the small gear is 1.5 inches and the radius of the large gear is 4.5 inches, we have;

Number of rotation of the small gear for each rotation of the large gear = 3 rotations

Therefore, number of rotation of the wheel = 3

Distance the bicycle travels = 3 × 2 × π × 10 inches = 60·π inches

The difference in distance traveled = 60·π inches - 40·π inches = 20·π inches

  • The distance traveled by the bicycle increases by 20·π inches ≈ <u>62.83 inches</u>

Learn more about gear transmission here:

brainly.com/question/14646065

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