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EastWind [94]
3 years ago
12

Line p passes through (8, -6) and is perpendicular to the line 2x + y = -7. The slope of line p is . The equation of line p is y

= 1/2x + ?.
Mathematics
1 answer:
Bingel [31]3 years ago
3 0

Answer:

y = (1/2) x -10

Step-by-step explanation:

Perpendicular lines are lines make right angles. The slopes of perpendicular lines are opposite reciprocals !

2x + y = -7 rewrite in form y=

y = -7 -2x

slope of this line is -2

perpendicular lines are opposite reciprocals so the line p has a slope = 1/2

line p passes through (8, -6) so plug in point into equation of p and get ?

y = 1/2 x +?

-6 =1/2(8) +?

-6 =4 + ? subtract 4 from both sides

-6-4 = ?

-10 = ?

y = (1/2) x -10

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eimsori [14]

Answer:

Your solution would be -1x^4 - 1x^3 + x^2 - 6x - 6.

Step-by-step explanation:

5 0
2 years ago
the sum of 49,000 naira is to be shared among A, B, and C in the ratio of 1:2:4, respectively. find how much each wilk receive.​
Natalka [10]

Answer:

#7000, #14000 and #28000 respectively

Step-by-step explanation:

#49000 to be shared in 1:2:4

49000 ÷ (1 + 2 + 4) = 49000/7 = #7000

A will get (7000×1) = #7000

B will get (7000×2) = #14000

C will get (7000×4) = #28000

3 0
3 years ago
The proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes was 0.9 −
kaheart [24]

Answer:

The proportion would be 0.1

Step-by-step explanation:

Given, the function that shows the proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes,

f(t) = 0.9 - 0.4\ln(t)

If t = 7 minutes,

f(7) = 0.9 - 0.4\ln(7)=0.9 - 0.77836=0.12164\approx 0.1

Hence, the proportion that remembered the number for 7 minutes is 0.1 ( approx )

8 0
3 years ago
What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
3 years ago
3x + 2 = 2x + 6<br><br><br> Please hurry
telo118 [61]

Answer:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

x  =  4

Step-by-step explanation:

I hope this helps! Have a good day!

3 0
3 years ago
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