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3 years ago

Which equation represents the line 3x - 2y = -8 in slope-intercept form?

Mathematics

1 answer:

blsea [12.9K]3 years ago

6 0

Answer:

The slope -intercept form of the equation is;

y = $\frac{3}{2}$ x + 4

Step-by-step explanation:

The slope-intercept form of an equation is;

y = mx + c

where m is the slope and c represent the intercept

To represent the equation given; 3x - 2y = -8 in its slope intercept form, we will follow the steps below:

3x - 2y = -8

subtract 3x from both-side of the equation

3x - 3x -2y = -3x - 8

-2y = -3x -8

Divide throught the equation by -2

-2y/-2 =-3x/-2 -8/-2

y = $\frac{3}{2}$ x + 4

The slope -intercept form of the equation is;

y = $\frac{3}{2}$ x + 4

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3 years ago

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Free_Kalibri [48]

Answer:

Step-by-step explanation:

Area of a square =

$s^2$

Perimeter =

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3 years ago

Determine the written description of the complement of the given event. When 13 computers are shipped, at least one of them is

julsineya [31]

Answer:

A. None of them are defective

True that's equivalent since none defective means 0 defective

Step-by-step explanation:

For this case we have a total of 13 computers and we define the event:

E= "At least one of them is defective"

When we say at last one means that can be 1,2,3,4,5,6,7,8,9,10,11,12 or 13

The complement for this case is E' ="None of them is defective"

Let's analyze one by one the possible options:

A. None of them are defective

True that's equivalent since none defective means 0 defective

B. None of them are free of defects

False thats note equivalent since that means all have defects and that's not the complement.

C. More than one of them are free of defects

False we are interested on the complement and on this case 1 or more defective is not the complement for this case.

D. All of them are defective

False the complement is defined as non of them defective and for this case is not the correct way.

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3 years ago

A 3.00-g copper penny at 25.0°C drops from a height of50.0 m to the ground. (

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(0.6)mgh=mcΔT
We see we can divide out the mass from each side
0.6gh=cΔT, then 0.6gh/c=ΔT
(0.6)9.81(m/s²)50m/385(J/kg°C) = 0.7644°C
since this is the change in temperature and it started at 25°C we get
T=25.7644°C
As you can see the result does not depend on mass. The more massive the copper object the more potential energy it will have to contribute to the heat energy, but the more stuff there will be to heat up, and the effect is that the mass cancels.

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3 years ago

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Vladimir79 [104]

Answer:

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Step-by-step explanation:

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2 years ago