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denpristay [2]
3 years ago
11

In the population of a particular country, the male-to-female ratio is 46 to 54. Write this ratio as a fraction in simplest form

.
Mathematics
1 answer:
Helen [10]3 years ago
5 0
23/27 because 46/54 diveded by 2 equals 23/27 which can not be simplified any further
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Write an equation for the line that passes through (- 3, 5) and is parallel to y = - 6x + 1.
soldier1979 [14.2K]

Answer:

y-5 = -6(x+3) OR y = -6x-13

Step-by-step explanation:

Let's use slope-intercept form to solve this problem.

Slope intercept form is the following:

y-y1 = m(x-x1)

x1 and y1 are given by the point in the problem.

x1 = -3, y1 = 5.

m is given by the equation in the problem. Lines that are parallel have the same slope. Thus,

m = -6.

If we plug these values into the equation for slope intercept form, we get the following:

y-5 = -6(x-(-3)) which becomes y-5 = -6(x+3)

This is an acceptable answer to the problem. However, point-slope form is also a way it can be written.

y-5 = -6x-18

y = -6x-13

3 0
3 years ago
Joseph tweets 13 times a day. define each variable and write an algebraic expression to describe the number of post after any gi
notka56 [123]

13 •X= # of tweets

X= number of days

3 0
3 years ago
An urgent detailed response is needed as soon
Misha Larkins [42]

Answer:

(a)180-135=45

45/360×100=12.5%

(b)135/360=27/72=9/24=3/8

(c)120/360×72=24

(d)180-120=60

60/360×72=12

I would appreciate if my answer is chosen as a brainliest answer

3 0
2 years ago
A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet length. What is the greatest number of 1
yan [13]
STEP 1:
Divide the length of the ribbon by the size of the pieces.

12 inches= 1 foot

= 9 ft ÷ 15 inch pieces
convert ft to inches
= (12)(9) ÷ 15
= 108 ÷ 15
= 7.2 pieces from one roll

STEP 2:
multiply the number of pieces that can be cut from one roll by the number of rolls

= 7.2 pieces * 5 rolls
= 36 pieces total from 5 rolls

ANSWER: The greatest number of 15-inch pieces that can be cut from five 9-foot rolls is 36.

Hope this helps! :)
4 0
4 years ago
1. Approximate the given quantity using a Taylor polynomial with n3.
Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

f(x) = x^{1/4}

The n-th order Taylor polynomial for function f with its center at a is:

p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}

As n = 3  So,

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}

p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} }  (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} +  (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}

p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} }  (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} +  (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}

p_{3} (x) = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6  

                                                                                  (0.0000018522752) (x-81)³

p_{3} (x)  =  0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

                                                                                                       (x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

p_{3} (94)  =  0.0092592593 (94) - 0.000042866941 (94 - 81)² +          

                                                                 0.00000030871254 (94-81)³ + 2.25

         = 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +    

                                                                                                                       2.25

         = 0.87037 03742 - 0.000042866941 (169) +  

                                                                      0.00000030871254(2197) + 2.25

         = 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

p_{3} (94)  = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute \sqrt[4]{94} as 94^{1/4} using calculator

Exact value:

E_{a}(94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94)  = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94)  = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94)  = 0.0001

4 0
4 years ago
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