Question

Evaluate for x = 3 and y = 4: x^-2y^2/x^0y^3 1/36 4/9 1024/9

Answer 1

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Evaluating the numerator and denominator before evaluating

Using the rule of exponents

$a^{-n}$ ⇔ $\frac{1}{a^{n} }$, $a^{0}$ = 1

Thus

$x^{-2}$y² ← substitute values into expression

= $3^{-2}$ × 4² = $\frac{1}{9}$ × 16 = $\frac{16}{9}$

and denominator

$x^{0}$$y^{3}$ = 1 × 4³ = 1 × 64 = 64

Now dividing

$\frac{16}{9}$ ÷ 64

= $\frac{16}{9}$ × $\frac{1}{64}$ ( cancel 16 and 64 )

= $\frac{1}{9(4)}$ = $\frac{1}{36}$