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vovangra [49]
3 years ago
9

What number should be added to 51 to get a sum -21

Mathematics
2 answers:
elena55 [62]3 years ago
6 0
51 + -72 = -21
Adding a negative seventy-two to fifty-one will give you a sum of negative twenty-one
Anastaziya [24]3 years ago
3 0
We can write out a formula in order to solve this. Since sum represents addition, if x represents the unknown number, we can write the formula: x+51=-21. Then, to solve for x, you would subtract 51 from both sides to get x=-72 which is the final answer. 
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Answer:

\frac{1}{230230}

Step-by-step explanation:

Given that in a certain​ lottery, an urn contains balls numbered 1 to 26

From this​ urn, 6 balls are chosen​ randomly, without replacement.

Bet amount 1 dollar and he selects a set of six numbers.

If these match with those chosen from the urn he wins (order does not matter)

Total ways of choosing 6 out of 26 = 26C6 = \frac{26!}{20!6!} \\=230230

The way he selects = 1

Hence probability of winning  =\frac{1}{230230}

with one ticket

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3 years ago
For each point identify the axis or quadrant where the point is located…
My name is Ann [436]

Answer:

quadrant ll

Step-by-step explanation:

A point on the y-axis will always have an x-coordinate of zero. Instructions: In the figure above, the point with coordinates (4,2) is located in quadrant I. The point with coordinates (-3,4) is located in quadrant II.

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sladkih [1.3K]
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4 0
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Read 2 more answers
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show that the sum of the x- and y- intercepts of any tangent line to the curve sqrt(x) sqrt(y) = sqrt(c) is equal to c.
expeople1 [14]
The answer is <span>√x + √y = √c </span>
<span>=> 1/(2√x) + 1/(2√y) dy/dx = 0 </span>
<span>=> dy/dx = - √y/√x </span>

<span>Let (x', y') be any point on the curve </span>
<span>=> equation of the tangent at that point is </span>
<span>y - y' = - (√y'/√x') (x - x') </span>

<span>x-intercept of this tangent is obtained by plugging y = 0 </span>
<span>=> 0 - y' = - (√y'/√x') (x - x') </span>
<span>=> x = √(x'y') + x' </span>

<span>y-intercept of the tangent is obtained by plugging x = 0 </span>
<span>=> y - y' = - (√y'/√x') (0 - x') </span>
<span>=> y = y' + √(x'y') </span>

<span>Sum of the x and y intercepts </span>
<span>= √(x'y') + x' + y' + √(x'y') </span>
<span>= (√x' + √y')^2 </span>
<span>= (√c)^2 (because (x', y') is on the curve => √x' + √y' = √c) </span>
<span>= c.  hope this helps :D</span>
5 0
3 years ago
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